Receive e-mail

or how to delete all email
please

I'm really confused what you're asking. Can you explain further please?

I imagine you used the smtplib module and its functions to send e-mail. Well, you use the poplib module and its functions to view and delete e-mail.

Use help('poplib') to get details.

A rather crummy example is at
http://docs.python.org/lib/pop3-example.html

I'm really confused what you're asking. Can you explain further please?

YOu know password and username.You want to delete all of the mails in the box using python...
I alredy know how to send e-mail,how to receive.Thanks for all help:D

Found code in one of the books in the CS library:

# view and delete e-mail using the POP3 protocol

import sys, getpass, poplib, re

# change according to your needs
POPHOST = "pop.domain.com"
POPUSER = "joedoe"
POPPASS = ""
# the number of message body lines to retrieve
MAXLINES = 10
HEADERS = "From To Subject".split()

# headers you're actually interested in
rx_headers  = re.compile('|'.join(headers), re.IGNORECASE)

try:
    # connect to POP3 and identify user
    pop = poplib.POP3(POPHOST)
    pop.user(POPUSER)

    if not POPPASS or POPPASS=='=':
        # if no password was supplied, ask for it
        POPPASS = getpass.getpass("Password for %s@%s:" % (POPUSER, POPHOST))

    # authenticate user
    pop.pass_(POPPASS)

    # get general information (msg_count, box_size)
    stat = pop.stat(  )

    # print some information
    print "Logged in as %s@%s" % (POPUSER, POPHOST)
    print "Status: %d message(s), %d bytes" % stat

    bye = 0
    count_del = 0
    for n in range(stat[0]):

        msgnum = n+1

        # retrieve headers
        response, lines, bytes = pop.top(msgnum, MAXLINES)

        # print message info and headers you're interested in
        print "Message %d (%d bytes)" % (msgnum, bytes)
        print "-" * 30
        print "\n".join(filter(rx_headers.match, lines))
        print "-" * 30

        # input loop
        while 1:
            k = raw_input("(d=delete, s=skip, v=view, q=quit) What?")
            k = k[:1].lower(  )
            if k == 'd':
                # Mark message for deletion
                k = raw_input("Delete message %d? (y/n)" % msgnum)
                if k in "yY":
                    pop.dele(msgnum)
                    print "Message %d marked for deletion" % msgnum
                    count_del += 1
                    break
            elif k == 's':
                print "Message %d left on server" % msgnum
                break
            elif k == 'v':
                print "-" * 30
                print "\n".join(lines)
                print "-" * 30
            elif k == 'q':
                bye = 1
                break

        # done ...
        if bye:
            print "Bye"
            break

    # summary
    print "Deleting %d message(s) in mailbox %s@%s" % (
        count_del, POPUSER, POPHOST)

    # close operations and disconnect from server
    print "Closing POP3 session"
    pop.quit(  )

except poplib.error_proto, detail:

    # possible error
    print "POP3 Protocol Error:", detail

hey, why i am getting this error..
can anyone explain me
Traceback (most recent call last):
File "popmail.py", line 14, in ?
rx_headers = re.compile('|'.join(headers), re.IGNORECASE)
NameError: name 'headers' is not defined

There is a booboo in the book, headers should be HEADERS.