This snippet shows a fast and efficient way to cut strings in substrings with a fixed length (note that the last substring may be smaller).
Cutting a string in equal pieces
import re
split5 = re.compile(r".{1,5}", re.DOTALL).findall
if __name__ == "__main__":
print split5('"Give me bacon and eggs," said the other man.')
# prints ['"Give', ' me b', 'acon ', 'and e', 'ggs,"', ' said', ' the ', 'other', ' man.']
Gribouillis 1,391 Programming Explorer Team Colleague
An alternative is this
splitIt = lambda d, s: [s[i:i+d] for i in range(0, len(s), d)]
if __name__ == "__main__":
print splitIt(5, '"Give me bacon and eggs," said the other man.') Gribouillis 1,391 Programming Explorer Team Colleague
The following benchmark shows that, on my machine, split5() is about 22% faster than splitIt()
# benchmark for split5 and splitIt (tested with python 2.6)
from timeit import Timer
import re
split5 = re.compile(r".{1,5}", re.DOTALL).findall
splitIt = lambda d, s: [s[i:i+d] for i in range(0, len(s), d)]
if __name__=='__main__':
t = Timer("split5('Give me bacon and eggs, said the other man.')", "from __main__ import split5")
print "split5: %.2f microsec" % t.timeit()
t = Timer("splitIt(5, 'Give me bacon and eggs, said the other man.')", "from __main__ import splitIt")
print "splitIt: %.2f microsec" % t.timeit()
""" my output --->
split5: 2.55 microsec
splitIt: 3.27 microsec
"""however, you can gain 0.2 microsecs by replacing range with xrange in splitIt()
lrh9 95 Posting Whiz in Training
I wonder how list slicing or struct.unpack() would work.
bumsfeld 413 Nearly a Posting Virtuoso
Seems to me that you also have to consider the time that re.compile() needs.
Be a part of the DaniWeb community
We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.