having an application that listens or can initiate connection

[brendanmcdonagh]

Hi all,

I am learning java and have developed a very basic message app which entails having a serversocket on one pc and a socket on another. This is working fine but now i want to go further and have them both to have the abiliy to wake the other up, so a kind of serversoket and socket on both. i ll paste my code for the client class and would really appreciate a pointer in which direction to go cos my head is a bit baffled wih this one!

/* 
 * Main.java 
 * 
 * Created on 28 October 2008, 13:19 
 * 
 * To change this template, choose Tools | Options and locate the template under 
 * the Source Creation and Management node. Right-click the template and choose 
 * Open. You can then make changes to the template in the Source Editor. 
 */ 
  
package clientside; 
  
import java.io.*; 
import java.net.*; 
import java.util.*; 
import javax.swing.*; 
import java.awt.*; 
import java.awt.event.*; 
  
  
public class Main implements ActionListener 
{ 
    public static JFrame aFrame; 
    public static JButton aButton; 
    public static JButton aButton2; 
    public static JTextField inputArea; 
    public static JTextArea output; 
  
    static ServerSocket server; 
    static Socket socket; 
    static PrintStream outStream; 
    static BufferedReader inStream; 
    static String aName;
    static String address;
    static int port;
    
    
  
    public Main() 
    { 
aFrame = new JFrame(); 
aFrame.setSize(500, 500); 
aFrame.setExtendedState(JFrame.MAXIMIZED_BOTH);
aFrame.setTitle("Input your message"); 
aFrame.setLayout(new BorderLayout()); 

aFrame.setVisible(true); 
  
aButton = new JButton(); 
aButton.setText("Press to send message"); 
aButton.setSize(200, 25); 
aButton.addActionListener(this); 
aFrame.add(aButton, BorderLayout.NORTH); 
  

  
 inputArea = new JTextField(50); 
inputArea.setVisible(true); 
inputArea.addActionListener(this);
aFrame.add(inputArea, BorderLayout.SOUTH); 
  
output = new JTextArea(25, 50); 
output.setVisible(true); 
aFrame.add(output, BorderLayout.CENTER);

  
  
    } 
public static void main(String[] args) 
{ 
try 
{     
    Main aMain = new Main();
    
    aName = JOptionPane.showInputDialog(null, "Enter Your Name : ",
"Input Box", 1);
    address = JOptionPane.showInputDialog(null, "Enter IP or address : ",
"Input Box", 1);
    String aPort = JOptionPane.showInputDialog(null, "Enter port to connect through : ",
"Input Box", 1);
    port = Integer.parseInt(aPort);
    
    
     socket = new Socket(address, port); 
    inStream = new BufferedReader(new InputStreamReader(socket.getInputStream())); 
    outStream = new PrintStream(socket.getOutputStream()); 
   
    
    
    String line;

      while  (!(line = inStream.readLine()).equals("exit") )
      {
        Main.output.append (line + '\n');
        
      }
    
     socket.close();
} 
catch (Exception anException) 
{ 
    System.out.println("Error: " + anException); 
} 
} 
public void actionPerformed(ActionEvent e) 
{ 
    String aString = Main.inputArea.getText();
    if((e.getSource() == aButton) || (e.getSource() == inputArea))
    {
 
    if((aString.equals("exit")) || (aString.equals(" exit")))
        { 
            
            
            try
            {
                
                System.exit(1);
                socket.close();
            }
            catch(Exception anException)
            {
                
            }
        } 
    else 
    { 
        Main.output.append (aName + " says " + aString + '\n');
        Main.inputArea.setText(" ");
        Main.outStream.println(aName + " says " + aString); 
        
        
    } 
}
}


}

ps. anyone answer this question as i ve been searching all day for an answer, how can i have text already in the inputdialog box which is a kind of default??

Kind Regards

Brendan