A number is called a proper divisor of N if M < N and M divides N. A positive integer is called perfect if it is the sum of its positive proper divisors. For example, the positive proper divisors of 28 are 1, 2, 4, 7, and 14 and 1+2+4+7+14=28. Therefore, 28 is perfect. Write a program to display the first 4 perfect integers.
I got this but the loop won't stop running.
public class PerfectNumbers
{
static int FIRSTPERFECT;
static int SECONDPERFECT;
static int THIRDPERFECT;
static int FOURTHPERFECT;
public static void main(String[] args)
{
findPerfect();
System.out.println(FIRSTPERFECT);
System.out.println(SECONDPERFECT);
System.out.println(THIRDPERFECT);
System.out.println(FOURTHPERFECT);
}
public static void findPerfect()
{
int count = 0;
int sum = 0;
int n = 1;
while(count <= 4)
{
int divisor = 1;
n = 1;
sum = 0;
while (divisor < n)
{
if(n % divisor == 0)
{
sum += divisor;
}
divisor++;
}
if(sum == n)
{
if(count == 1)
{
FIRSTPERFECT = n;
count++;
n++;
}
else if(count == 2)
{
SECONDPERFECT= n;
count++;
n++;
}
else if(count == 3)
{
THIRDPERFECT = n;
count++;
n++;
}
else if(count == 4)
{
FOURTHPERFECT = n;
count++;
n++;
}
}
else
n++;
}
}
}