delete the last and first line in an interval

[dododero]

hey all
well i have been facing this problem for days ...i have written a program where i am suppose to read a specific number of lines within different intervals and count the number of occurance of r and s and then divide r by s. The program is running correctly but the problem takes place in such a case where s line is at the end of the interval and r line is received at the begining of the second interval giving me a % higher than 100 therefore i need to remove the last line of the interval and the first line of the second interval
plz help

[WolfPack]

Please post the code.

[dododero]

ok will post now

[Schol-R-LEA]

Yes, it should allow you to paste code; what browser are you using?

If you look at the editing window, you should see a button marked 'Code'. If you click on that, it will come up with a pop-up window for editing the code in. If you have pop-ups blocked, or are using NoScript or a similar script blocker, that could be the cause of the problem.

Note also that you may not need to paste the whole program, if there is a specific function or section that you know is the source of the issue.

[dododero]

thank u here 's the code

#include <iostream>
#include <fstream>
#include <iomanip>
#include <cmath>
#include <string>
#include <sstream>
#include <vector>

    using namespace std;

int main()
{
    ofstream fout("TPDR[3-4-30].tr");
    ifstream fin("TTEST.tr");// if u use this as ur input file u will always get ur num as 6 because the range stops at 50 therefore u will get the throughputs calculated as 0z 
    ofstream fOut("TPDR30(3-4).tr");
    ofstream MYFILE("TPDR(3-4).tr");

    if (!fin)
    {
        cout << "input file not open" << endl;
        return 1;
    }

    fout << fixed << setprecision(9);
    fOut << fixed << setprecision(9);
    cout << fixed << setprecision(9);
    MYFILE << fixed << setprecision(9);

    double timelimit = 0.0;    // ending time of first block of data
    double timeincr  = 10.0;   // duration of each block of data

    string s1, s2, s3, sequenceno1,sequenceno2, s4, s5; // dummy variables to hold unwanted data 
    string line,oldline;

    char   type;   
    double time;   
    int    bytes;  
    int num = 0;
    istringstream ss;
    double received[21] = {0.0}; 
    double send[21] = {0.0}; 
    int drop[21] = {0}; 
    double Re[21]= {0.0};
    double Se[21] = {0.0};
    double De[21] = {0.0};
     int R = 0;
     int S = 0;
    double PDR =0.0;
    double PDRR[21] = {0.0};
    int Range; 


    //------- Priming read. Get first line.
    getline(fin, line);
    ss.str(line);
    ss >> type >> time;

    while (fin)
    {
        while (ss && time <= timelimit)
        {

            //------------- process the line here ------------------
                 // ss >> s1 >> s2  >> s3 >> s4 >> s5 ;



         if (type == 's') {

                  ss >> s1 >> s2 >> s3 >> sequenceno1 >> s4 >> s5;
                      oldline = line;
                      send[num]++; 
                      S = send[num]; 
                      Se[num] = S; 
                  }


               if (type =='r') {

                      ss >> s1 >> s2 >> s3 >> sequenceno2 >> s4 >> s5;
                  if ((time < timelimit)&&(sequenceno1 == sequenceno2)) {
                      cout << sequenceno1 << "   " << sequenceno2 << "    " << time << "    " << timelimit << ".\n";
                     received[num]++;
                     R = received[num];
                     Re[num] = R;
                     PDR = Re[num]/ Se[num];
                     PDRR[num] = PDR*100;

    fout << "Received = " << Re[num] <<"     " << time <<"    " << "Send= " << Se[num] << "  " << "Packet Delivery Ratio" << PDRR[num]  << "    "<< "sequenceno1 =" << sequenceno1 << "      "<< "sequenceno2 ="  << sequenceno2 << ".\n"; 


                }

                }

            //------------- end of process, now read the next line -----

            if (getline(fin, line))
            {
                ss.clear();             // clear all flags
                ss.str(line);
                ss >> type >> time;
            }
            else
            {
                ss.clear(ios::failbit); // set the fail flag

            }

        }



        timelimit += timeincr; // increment limit to next value
        cout << timelimit << ".\n\n";
        num++; 
        fout << "\n------------------\n";
        fout << "time limit: " << timelimit << endl;
        cout << "num = " << num << ".\n";
    } 

   // ..... Writting the Range and PDR within each Range in a separate File .....

for (Range = 10,num =1; Range <= 200, num <=20; Range+=10, num++) {
    fOut << Range << "     " << PDRR[num] << ".\n";
 } 

 double average = 0.0;
 double TPDR = 0.0;

 for (num = 1; num <=20 ; num++) {   // For loop to compute the Total PDR within each Range 
     TPDR += PDRR[num]; 
    // cout << "TPDR" << TPDR << "%" << ".\n"; 
 }

 average = TPDR /(num-1);
 cout << "average = " << average << "%" <<  ".\n";// Compute Average PDR 

    cout << "Done" << endl;
    return 0;
}

[dododero]

here's the file i am using

s 167.204369958 7 MAC --- 29867 tcp 630 [13a 8 7 800] ------- [7:2 8:1 32 8] [330 0] 0 1..
r 167.209410087 8 MAC --- 29867 tcp 572 [13a 8 7 800] ------- [7:2 8:1 32 8] [330 0] 1 1..
s 167.212674795 7 MAC --- 29868 tcp 630 [13a 8 7 800] ------- [7:2 8:1 32 8] [331 0] 0 1..
r 167.217714923 8 MAC --- 29868 tcp 572 [13a 8 7 800] ------- [7:2 8:1 32 8] [331 0] 1 1..
s 169.998902881 7 MAC --- 30344 tcp 630 [13a 8 7 800] ------- [7:3 9:0 32 8] [147 0] 0 1..
r 170.00392963 8 MAC --- 30344 tcp 572 [13a 8 7 800] ------- [7:3 9:0 32 8] [147 0] 1 1..
s 170.162989092 7 MAC --- 30466 tcp 630 [13a 8 7 800] ------- [7:2 8:1 32 8] [334 0] 0 1..
r 170.168029172 8 MAC --- 30466 tcp 572 [13a 8 7 800] ------- [7:2 8:1 32 8] [334 0] 1 1..
s 170.181482383 7 MAC --- 30467 tcp 630 [13a 8 7 800] ------- [7:2 8:1 32 8] [335 0] 0 1..
r 170.186522463 8 MAC --- 30467 tcp 572 [13a 8 7 800] ------- [7:2 8:1 32 8] [335 0] 1 1..
s 178.013133357 7 MAC --- 32131 tcp 630 [13a 8 7 800] ------- [7:2 8:1 32 8] [340 0] 0 1..
r 180.725285180 8 MAC --- 32716 tcp 572 [13a 8 7 800] ------- [7:2 8:1 32 8] [341 0] 1 1..

The problem takes place in such case where the s lines comes at the end of my range and the r lines comes at the begining of the second range leading to an increase in the number of the received lines than the send which gives a % higher than 100%
in this snapshot example i want to delete these two lines
s 169.998902881 7 MAC --- 30344 tcp 630 [13a 8 7 800] ------- [7:3 9:0 32 8] [147 0] 0 1..
r 170.00392963 8 MAC --- 30344 tcp 572 [13a 8 7 800] ------- [7:3 9:0 32 8] [147 0] 1 1..

plz help me out its annoying me for days
thanx in advance

[David W]

The first step in solving a problem is a clear statement of what is required.

You wrote this at the top:

... been facing this problem for days ... have written a program where ... suppose to read a specific number of lines

within different intervals

What does this

within different intervals

mean?

Does it mean, as you read a file, line by line, counting the lines, from say line 1 as the first line ...

that you are take some (user specified) 'sample of lines' ... say lines n to line (n+size-1)

(You could copy these lines into a tmp vector of lines ... and pause your file scanning while you process that tmp vector ...)

and count the number of occurance of r and s

Ok ... process that tmp vector of lines, and report

and then divide r by s.

If that is 'your problem' ... can you see now that it is easy to handle it this way?

[dododero]

thank u 4 ur reply .... well what i meant by interval is the range of time say for example i have a file of 200s i should read my lines every 10s (in the ex above my first interval is from 160-170 and my second interval is from 170-180 and so on. The problem takes place when the s line comes at the end of the first interval and the r line comes at the begining of the second interval ...This will lead to incorrect counting as the number of r lines are suppose to be less than the s lines
i need to check if the s line comes at the end of the interval and is not followed by the r within the same interval if so delete
In the second interval i need to check if the interval starts with the r line and not s if so delete it
These lines are not at the end of my file therefore any ideas how can i do putting in consideration that my file is big
thanx in advance

[David W]

Ok ...

still not clear what you are trying to do ...

suppose you have lines in a big file that look like this:

sxxxxxxxxxxxxxx...
rxxxxxxxxxxxxx...
rxxxxxxxxxxxxxx....
sxxxxxxxxxx............
sxxxxxxxxxxxxxx............
r............

to 100,000,000 + lines

ok ... suppose you are taking 2 successive samples for the intervals of 0.001 seconds each

you could read in all the lines into a list of lines ...for 0.002 secs ....

then process that list ... 1st half & 2nd half