HI,

I have a form that has more than one checkbox.
I need to store the checkbox value in mysql.
I am using php code.I am not sure of the code of storing the checkbox value to the database.
Your help will be much appreciated.
Thanks

Tryphy

Can you show us your code ?

Hopefully this will give you an idea that you can adapt into your code, if not then ask again

<?php
if(isset($_POST['box01']))
{
$box01 = 1;
}
else
{
$box01=0;
}
if(isset($_POST['box02']))
{
$box02=1;
}
else
{
$box02=0;
}

$insert=mysql_query("
INSERT INTO tablename('field01', 'field02')
VALUES ('" . $box01 . "', '" . $box02 . "'");

Hopefully this will give you an idea that you can adapt into your code, if not then ask again

<?php
if(isset($_POST['box01']))
{
$box01 = 1;
}
else
{
$box01=0;
}
if(isset($_POST['box02']))
{
$box02=1;
}
else
{
$box02=0;
}

$insert=mysql_query("
INSERT INTO tablename('field01', 'field02')
VALUES ('" . $box01 . "', '" . $box02 . "'");

Instead of $box01=1 and $box01=0, you can assign the value of the checkbox itself! $box01=$_POST['box01']; And this isn't useful if you have, say, 10 checkboxes. The best thing would be to have an array of checkboxes !

You make a good point, but would that store 'checked' or 'unchecked' in the database??

You make a good point, but would that store 'checked' or 'unchecked' in the database??

No. It will store the value of the checkbox. Eg.

<?php
print "<pre>";
print_r($_POST);
print "</pre>";
?>
<form method="POST" action="test.php">
<input type="checkbox" name="check[]" value="100">100 <br />
<input type="checkbox" name="check[]" value="200">200 <br />
<input type="checkbox" name="check[]" value="300">300 <br />
<input type="submit" name="submit" value="submit">
</form>

Cheers,
Naveen

<?php
include("config.php");

$pid=$_POST;
echo $pid;
$desc=$_POST;

$sql="select * from `ph_category` where `id`='$pid'";
$q=mysql_query($sql);
$row=mysql_fetch_array($q);
$var=$row;


$path="Uploads/";
$path=$path.basename($_FILES);
if(move_uploaded_file($_FILES,$path))
{
$filename=$path;
echo 'done';

}
$var1=$_FILES;
$img=$_FILES;;
echo "<img src='$img'>";
include("checkbox.php");
if(isset($_POST))
{
c1.checked="1";
}
$sql="INSERT INTO `ph_cate` VALUES (' ','$pid','$var1','$var','$desc',' ',' $c1', ' $c2',' ') ";

$q=mysql_query($sql) or die(mysql_error());
echo "Data Submitted Successfully...";
?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<?php
include('confi.php');
$sql = "select * from user";
$result = mysql_query($sql);
?>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<script type="text/javascript">
function showUser(str)
{
if (str=="")
  {
  document.getElementById("txtHint").innerHTML="";
  return;
  } 
if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
else
  {// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function()
  {
  if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
    document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
    }
  }
xmlhttp.open("GET","getuser.php?id="+str,true);
xmlhttp.send();
}
</script>
</head>

<body>

<form><select name="users" onchange="showUser(this.value)">
      <option name="student" value=''>Name list</option>
  <?php while($nt=mysql_fetch_array($result))
  {
       ?>
    <option value="<?php echo $nt[id] ?>"><?php echo $nt[Name]?></option>    



<?php
  }
  ?>
  </select>
   </form>
   <br />
  <div id="txtHint"><b>Person info will be listed here.</b></div>
</body>
</html>
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