javascript and php

Question

wdev 0 Newbie Poster

15 Years Ago

hey guys,

This question might be discussed over thousand times but please help me on this one!
I have a customer registration (html) page on which I have included form level validations using java script. On click of the submit of this page control goes to regist.php where I run a query to insert records into mysql database.

I have a userid field on the html page which I want to validate against database of mysql.

How can I get the php array from mysql database of existing userids and compare it using javascript to the one recently entered?

Please explain,

Thanks

php

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Latest Post 15 Years Ago Latest Post by wdev

somedude3488 228 Nearly a Posting Virtuoso

15 Years Ago

ajax, or use php to validate your form.

i am leaving so i wont be able to provide examples right now. hopefully someone else can help, i was just trying to point you in the right direction.

R0bb0b 344 Posting Shark

15 Years Ago

You can use a php loop to fill a javascript array, something like this:

<script language="javascript" type="text/javascript">
var jsarray = Array(<?
$jsarray = "";
while ($row = mysql_fetch_assoc($result))
{
	$jsarray .= "\"" . $row['id'] . "\", ";
}
$jsarray = substr($jsarray, 0, -2); //eliminate the last ", "
echo $jsarray;
?>);
</script>

Then you that js array that you can compare to your original js array.

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wdev 0 Newbie Poster · Answer 1 · 2008-07-10T10:25:24+00:00

wdev 0 Newbie Poster

15 Years Ago

thanks a lot!

wdev 0 Newbie Poster · Answer 2 · 2008-07-10T10:31:12+00:00

Thanks a lot to both of you.
R0bb0b,
I have couple of questions.

Should we write the above code in a function in the <head> section?
Should we connect to the database in the php code itself?

thanks,

Shanti C 106 Posting Virtuoso · Answer 3 · 2008-07-10T10:46:35+00:00

Yes,we can write our script code in head tags...
And database connection is like this:

<?
global $link; 
$link = mysql_connect('localhost', 'root', '1234') ; // Connection
mysql_select_db("mydb") or die(mysql_error()); // Selection of database

//for closing
<?
if(isset($link))
{
mysql_close($link);
}
?>

?>

We can write database connection in our php page at top of the page by using <? ?> tags...

R0bb0b 344 Posting Shark · Answer 4 · 2008-07-10T11:24:30+00:00

Thanks a lot to both of you.
R0bb0b,
I have couple of questions.
Should we write the above code in a function in the <head> section?
Should we connect to the database in the php code itself?
thanks,

That's probably what I would do is put it in a function and then you can call it anywhere. You don't necessary have to call it in the head but that's where I would do it. Tested this on my database and it works fine:

<?php
include("inc/functions.inc");
$db = dbconn();

function getJSArray()
{
	global $db;
	$return = "";
	$query = "select texttagpk from texttag";
	$result = mysql_query($query, $db);
	$return .= '<script language="javascript" type="text/javascript">
				var jsarray = new Array(';
	while ($row = mysql_fetch_assoc($result))
	{
		$return .= "\"" . $row['texttagpk'] . "\", ";
	}
	$return = substr($return, 0, -2); //eliminate the last ", "
	$return .= '); </script>';
	return $return;
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Untitled Document</title>
<?= getJSArray(); ?>
</head>

<body>
</body>
</html>

wdev 0 Newbie Poster · Answer 5 · 2008-07-11T03:06:26+00:00

Thanks guys. I appreciate your help.

This is what I have done so far...
a 'dbcon.inc' file

<?php


function getData()
{
//connect to the database
$db = mysql_connect("localhost","root","");
mysql_select_db("xyz", $db);



}
?>

a html file to create array

<?php


include("dbcon.inc");


$db = getData();


function getJSArray()


{


global $db;


$return = "";


$query = "select userID from customer";


$result = mysql_query($query, $db);


$return .= '  <script language="javascript" type="text/javascript">
var jsarray = new Array( ';


while ($row = mysql_fetch_assoc($result))


{


$return .= "\"" . $row . "\", ";


}


$return .= '); </script>';


return $return;


}


?>


<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">


<html xmlns="http://www.w3.org/1999/xhtml">


<head>


<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />


<title>Untitled Document</title>


<?= getJSArray(); ?>


</head>


<body>


</body>
</html>

but when I run this html ...............
I get this printed on the page....

var jsarray = new Array() '; while ($row = mysql_fetch_assoc($result)) { $return .= "\"" . $row . "\", "; } $return .= '); '; return $return; } ?>

What is that I am missing?

Thanks,