I am trying to square each number in the list under nums. But I don't know how to do it. I got this so far:
def squareEach(nums):
for i in nums:
y=i*i
return yWhat is happening here is it's counting how many numbers are in the list and then squaring it.I want the square of each number in the list....please help!thanks!
def squareEach(nums):
return [i*i for i in nums]Thanks!:) But what if it's in the arrangement like mine, how would you write that with the same output as yours?
Something like:
def squareEach(nums):
squares=[]
for number in nums:
squares.append(number*number)
return squareswhat if <list>.append(x) is not used, is there any other way to write this code in that arrangement? I'm sorry...I'm new to this and I haven't learned that yet..well now i have but I can't use that yet. thanks!
def squareEach(nums):
squares=[]
for number in nums:
squares += [number * number]
return squareswhat if <list>.append(x) is not used, is there any other way to write this code in that arrangement? I'm sorry...I'm new to this and I haven't learned that yet..well now i have but I can't use that yet. thanks!
You could print them out instead of returning the value or build the result with +, which is not the recommended way. Or you could use recursion.
def squareEach(nums):
squares=[]
for number in nums:
squares+=[number*number]
return squares
# test it
print zip(range(20),squareEach(range(20)))We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.