The network IP address allocated to a network administrator is 172.31.0.0/20.
Which portion of the address is the network, which part is the host and which is the subnet mask?
n = network
s = subnet
h = host
nnnnnnnn.nnnnnnnn.nnnnssss.hhhhhhhh
would that bet correct?
I think this article will put you on the right track:
http://searchnetworking.techtarget.com/definition/subnet
and this:
This might help also:
ID # Bits Number Hosts Usable Hosts Netmask Note
6 /6 67108864 67108862 252.0.0.0
7 /7 33554432 33554430 254.0.0.0
8 /8 16777216 16777214 255.0.0.0 Class A Network
9 /9 8388608 8388606 255.128.0.0
10 /10 4194304 4194302 255.192.0.0
11 /11 2097152 2097150 255.224.0.0
12 /12 1048576 1048574 255.240.0.0
13 /13 524288 524286 255.248.0.0
14 /14 262144 262142 255.252.0.0
15 /15 131072 131070 255.254.0.0
16 /16 65536 65534 255.255.0.0 Class B Network
17 /17 32768 32766 255.255.128.0
18 /18 16384 16382 255.255.192.0
19 /19 8192 8190 255.255.224.0
20 /20 4096 4094 255.255.240.0
21 /21 2048 2046 255.255.248.0
22 /22 1024 1022 255.255.252.0
23 /23 512 510 255.255.254.0
24 /24 256 254 255.255.255.0 Class C Network
25 /25 128 126 255.255.255.128
26 /26 64 62 255.255.255.192
28 /28 16 14 255.255.255.240
27 /27 32 30 255.255.255.224
29 /29 8 6 255.255.255.248
30 /30 4 2 255.255.255.252
Hi Bangor_boy.
The classful network is 172.31.0.0/16.The network you have is already subnetted and that's why it's 172.31.0.0/20 which will actually give you 16 subnets since 4 bits have been borrowed from the host bits of the /16 network. The 16 subnets are 172.31.0.0/20,172.31.16.0 up-to 172.31.240.0/20(note that it's a 16 jump). Each of the 16 subnets will have 4096 hosts.
So it should be nnnnnnnn.nnnnnnnn.sssshhhh.hhhhhhhh.
Hope this will help and also that you've learnt something more.
Would this be the same using subnet 0 as i've worked my way through a few questions and then seen i should be using this and im confused again
I.P subnet zero is usable by default on Cisco Routers and I believe also on Juniper routers. So you can use it.
not much more to add except that we know the following for the given subnet
--
network ID: 172.31.0.0 (the 0.0 subnet of the classful 172.31.0.0 network)
subnet mask: 255.255.240.0 (11111111.11111111.11110000.00000000)
range of host IDs in this subnet: 172.31.0.1 - 172.31.15.254
broadcast address: 172.31.15.255
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