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What do you want to do in Tkinter other than the menu, and what do you want the entire program to do? A couple of comments: [code] def __init__(self,denom,value): self.Denomination = "CENTS" self.Value = 0 ## if the value is not 25 or 50 then self.Value remains at zero ## …

It should be [code] if b in line: print line.find(b)[/code]as the two statements are related.

And what happens when they guess "books" and it is "bones". You have to eliminate a letter that is found or it will "find" two o's when there is only one. Since we don't know what kind of containers realWord and guess are, I am using a list since they …

[code]def create_deck(): deck = [] for i in range(10): for color in ['blue','green','red','yellow']: if i == 0: card = StandardCards(color,i) deck.append(card) else: card = StandardCards(color,i) deck.append(card) card = StandardCards(color,i) deck.append(card) [/code]You create 1 + 2*9 cards for each of the colors=76 cards, plus the wild cards.

You should not use "i", "l", or "O" for variable names as they can look like digits as well as other letters. This code is a good example of why. You will have to discover the problem yourself (the problem may be caused by being too lazy to key in …

That is not list append, but a [url=http://www.java2s.com/Code/Python/List/Listinsertix.htm]list insert[/url]. Another way to do it to create a new, third list by appending list 1 until "+++++++" is found, then append list 2, then append the rest of list 1.

[quote]but when the chunk is inserted, each item gets a "\n"[/quote]Python does not write a "\n" to a file as it does with a print statement. If there is a "\n" it must be in the string, so print the string so you know what is being added. Also, ImageMagick …

Use a function to draw the rectangles. Within a loop, send the function the parameters for the smaller rectangle, then send the parameters for the 4 larger rectangles, and finally a smaller rectangle. It will draw a row for every iteration in the loop.

[quote]File "par.py", line 6 line = line.replace(" ^[/quote]Note the mark at the beginning of the line, which usually means the problem is the previous line. [code]## test with this first for line in fileinput.FileInput(files="./test.txt"): print line # ## iterates over the lines of all files listed in sys.argv[1:] for line …

The main problem is that you don't pass board to the function, update it, and then return the new board. Consider using a list instead of a string as it makes things much easier. Also use a loop to get the input instead of 5 separate sets of statements. [code]import …

lpr is the print spooler on Linux so you should be able to do something similar to [code]import subprocess subprocess.call("lpr "+filename.txt, shell=True) [/code]"man lpr" will give you all of the print options that lpr supports.

For starters, this does not make sense [code] if line.count('<') == 0: line [/code]Here, you are splitting a list which should yield an error message that says you can only split strings, not lists. [code] else: frag1 = line.split('<')[1] try: frag2= frag1.split('>') [/code]And why are you implementing all of the …

Note how the variables increase by one in this code (but in your example output they decrease??) [code] for a in range(n, 0, -1): print(a, end="\n") for i in range(n+1, 0+1, -1): print(i, end="\n") for j in range(n+2, 0+2, -1): print(j, end="\n") for f in range(n+3, 0+3, -1): print(f, end="\n") …

[quote]All he needed was $1,500.00 USD for the plain ticket.[/quote]It was smart to ask her for the money for a plain ticket instead of the more expensive elaborate ticket.

"grid is not an instance variable, but a class variable. That means that it is common to all class instances. See the example below. I think you want to use an instance variable. [code]class Board: SIZE = 3 grid = [] def __init__(self, var): self.grid.append([var]) print self.grid b = Board("b") …

If you want to save more than one grade per student, use a dictionary of lists. [code]marks = {"alice" : ["A+", "B-"], "smith" : ["A", "A"], "daemon" : ["B+", "B"], "lily" : ["B", "C"] } [/code]

Assuming self.cards is a list: [code]cards = range(1, 53) print cards cards_shuffled = cards[26:] + cards[:26] print cards_shuffled # # or to modify your code (this assumes cards are numbered 1-52, not 0-51) cut_deck = [] for loop in range(26, 53): ## 53, __not__ 52 = 1-52 cut_deck.append(self.__cards[loop]) for loop …

A hint regarding accessing the dictionary. [code]class Polynomial: def __init__(self, *termpairs): self.termdict = dict(termpairs) print (self.termdict) def print_result(self, key): print "%dx^%d" % (key, self.termdict[key]) if __name__ == '__main__': d1 = Polynomial((2,3), (4,5), (8,9)) ## extract and sort keys to process in numerical order keys=d1.termdict.keys() keys.sort() for key in keys: d1.print_result(key) …

There are [url=http://www.daniweb.com/software-development/python/threads/162038]examples on Daniweb[/url] that you can use as well as on the web. This is a very simple and common question. [quote]I am not using 'textctrl' as i will have to create a seperate frame , add buttons and add functionality to that again which is again tedious.[/quote]Laziness …

It's not obvious what you want to do. If you want to capitalize the first word of the sentence: [code]test_recs = "The quick brown fox jumped over the lazy dog. test sentence number two." new_rec_list=[] for sentence in test_recs.split(". "): if len(sentence): new_sentence = sentence.strip().capitalize() new_rec_list.append(new_sentence) print ". ".join(new_rec_list) [/code]

If you want to access or print all the numbers, append them to a list test_list = [1, 2] ## Fibs can be started with any 2 numbers test_list.append( test_list[-1]+test_list[-2] ) print test_list

[QUOTE=Jetster3220;1694474]still having problems with the program... Won't go past question three and checking answers section wrong[/QUOTE] Dont' know what "Won't go past guestion three" means. On input, on writing, on checking answers? And have you already created the file "few_questions.txt" with the questions in it (that could be the cause …

You can do it this way, but it would be better to use a for() loop: [code]ctr = 0 line1 = myFile.readline() while line1: myOut.write(line1.strip("\n")) ## 4 records without end-of-line ctr += 1 if ctr > 3: ## 4 records written myOut.write("\n") ctr = 0 line1 = myFile.readline() [/code]

The easiest to understand is to store the previous record, and find the number for the record previous to the ">" record. [code]seq=""">s1\n MPPRRSIVEVKVLDVQKRRVPNKHYVYIIRVTWSSGATEAIYRRYSKFFDLQMQMLDKFP MEGGQKDPKQRIIPFLPGKILFRRSHIRDVAVKRLIPIDEYCKALIQLPPYISQCDEVLQ FFETRPEDLNPPKEEHIGKKKSGNDPTSVDPMVLEQYVVVADYQKQESSEISLSVGQVVD\n >s2\n MAEVRKFTKRLSKPGTAAELRQSVSEAVRGSVVLEKAKLVEPLDYENVITQRKTQIYSDP LRDLLMFPMEDISISVIGRQRRTVQSTVPEDAEKRAQSLFVKECIKTYSTDWHVVNYKYE DFSGDFRMLPCKSLRPEKIPNHVFEIDEDCEKDEDSSSLCSQKGGV\n""" split_seq = seq.split("\n") name = "" pattern = 0 previous_rec = "" for line in split_seq: line = line.strip() if …

One way is to use a StringVar. When you change it's contents, the change shows up on the GUI. And you should [url=http://effbot.org/tkinterbook/button.htm]read up on buttons[/url] as yours don't do anything when clicked. [code]from Tkinter import * from tkFileDialog import * class Game(): def __init__(self,root): self.root = root self.var1 = …

That's because there is an infinite loop in the program. Because "n" does not change, the while loop never exits. We have no way of knowing how you want to change the number if it is divisible by 2, or how you want to change it if it is not. …

Open and read the file once into a list at the start of the program. If there are adds, simply add them to the list. Write the file once at the end of the program. I am guessing that each record in the file will contain the student's name and …

I like this explanation of the parts of a function [url]http://www.tutorialspoint.com/python/python_functions.htm[/url]. Tutorials are there for a reason, i.e they can be written once and read many times by many people. Start a list of good tutorials so you don't have to post to a forum with questions about very basic …

I would suggest that you print word_freq. You possibly want to use setdefault instead of .get although there is no description of what you want this part of the code to do so there is no way to tell for sure. [code] for word in word_list: word_freq.setdefault(word.lower(),0) word_freq[word.lower()] += 1 …

Use a list of lists [code]card_list = [ [], [], [], [], [], [], [] ] x = 0 while x < 7: ## number of cards to be dealt to each hand ## each for() loop deals one card to each of the hands in card_list for ctr in …

Adding print statements will tell you what is going on. [code]for line in in_file: print "line =", line number = line.split() print "number =". number for col in number[0]: print "comparing", col, number[3] if col == number[3]: print number[0], number[1], number[2], number[4] [/code]

Put the objects in a list or dictionary and draw the appropriate object each time there is a miss. [code]win = GraphWin("Test", 500, 650) start_x = 200 object_dict = {} obj = Circle(Point(start_x,200),50) object_dict[0] = obj ctr = 1 for ln in ((0, 150, 0, 100), (0, 100, -100, 100), …

[code] content = row[0] + row[4] + row[5] + row[11] + row[12] + row[13] + row[16] + row[17] + row[22] csv_out.writerow( content )[/code]The above uses 9 fields. [quote]# I want it to save the file in csv format as: 1,2,yhnujmik,2121212121[/quote]This has 4 fields. [quote]however the code is generating this: 1,2,y,h,n,u,j,m,i,k,2,1,2,1,2,1,2,1,2,1[/quote]This …

[QUOTE=A.D.M.I.N;1690514]I mean how could I do this?[/QUOTE] Pass a parameter to the function, and return the desired result as many times as you want. You can start at "A first program" [url=http://www.pasteur.fr/formation/infobio/python/ch01.html#d0e115]here[/url] and also [url=http://www.pasteur.fr/formation/infobio/python/ch08.html]here[/url] and [url=http://www.pasteur.fr/formation/infobio/python/ch11s02.html]here[/url]. No on wants to do this for you as it is simple and …

Post the code you have so far along with any problems.

Post the formula that you would like to use for solving the problem. The most common method is layer by layer. Also, post the code here if you want people who don't have, or want to deal with MS Windows archiver to respond.

I prefer using a list. [code]word1 = "hangman" blank_word = [] for c in word1: blank_word.append('_') print blank_word for guess in ["a", "b", "n"]: print("testing", guess) for ctr in range(len(word1)): if guess == word1[ctr]: blank_word[ctr]=guess print(" ".join(blank_word)) [/code]

I think you want something like this, but post back if I do not understand [code]## store the recs in a set to make look up fast ## this assumes no two records are the same recs_list = open('event_from_picks', 'r').readlines() event_set = set(recs_list) for key, list_of_numbers in event_dict.items(): if key …

Since words are not very long, it is not a problem to iterate through the entire word and keep track of the position of the first vowel, and if there is a consonant. [code] first_vowel = -1 ## location of first vowel consonant_found = False ## assume no consonants t …

There are not any answers presumably because no one uses 5 nested dictionaries. State what you are trying to do and why a 5-deep dictionary is necessary, along with a simple example, 184 lines of code is more than someone wants to wade through for a question like this, so …

First have you tried difflib or something like it, as this has to have already been done by someone? If you are using readlines to read the files or reading the recs into a list, we don't know, then these conditions will never be true, because letter or letters does …

You open movies.txt twice and don't close either one. Delete line #5, the first open is not used. It would work better if you open the file in a function. [code]def view_existing(): all_movies = open("movies.txt", "r").readlines() ## print the all_movies list and allow the user to select one ## something …

Can't you just take the difference between price and priceW, and then multiply by rate. If you want to print out every increment, then some kind of loop is necessary, and should be in a function that you pass the prices, rate, and literal to print, since both calculations are …

You hit the Enter key without any data. You should know what the code does even if you get it from someone else. What is necessary to exit in this code? [code] in_str="" while in_str != "q": [/code]

You do not allow for an equal condition in the commented code. Since you did not say what "wrong" is, we can only guess.

[quote]for i in (hold2.split()[0:25]): AttributeError: 'list' object has no attribute 'split'[/quote]You want to split, etc. "i", not the list "hold2".

I think graphics has an undraw() method, you'll have to check to be sure, but set a variable to True or False. If True, call function_1 which undraws "standing" and draws "jump" and set variable=False. If False, call function_2 and do the reverse. It would be much easier if all …

This question is in all of the other forums and so has probably already been answered.

sys.exit() is never a good idea. In this case Tkinter's quit() is the preferred way to exit. The program runs on my Slackware system with this modification to endProgram()[code] def endProgram (self): if self.state == 0: self.master.quit() else: print ("state is not zero -->", self.state) [/code]

[quote]but i know how to compare and find the age i just dont know how to show the name of the person[/quote]You want to use [code]for key, item in a_dictionary.items(): # # or for key in a_dictionary: if a_dictionary[key] == age: [/code]