Alicito 27 Light Poster

well friend I think thats you can do it by loops , playing with the cout''s also by using ( \t ) - ( \n ) .........
I think that your solution was the basic step for all others shapes
I will list some for you , I hope that its allowed

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*
  ***
*****
    *
    *
    *
    *
    *
#include <iostream>
using namespace std;
//This program was written by the Programmer Ali Denno
void main ()
{
	int x, k, i, j;
	for(k=1;k<=8;k++)
	{
		if(k!=2 && k!=3)
		{
			for(i=1;i<=5;i++)
			{
				if(i==3)
					cout<<"*";
				else
					cout<<" ";
			}
			cout<<endl;
		}
		else
			if(k==2)
			{
				for(j=1;j<=5;j++)
				{
					if(j==1 || j==5)
						cout<<" ";
					else
						cout<<"*";
				}
				cout<<endl;
			}
			else
			{
				for(x=1;x<=5;x++)
				{
					cout<<"*";
				}
				cout<<endl;
			}
	}
}

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***
  *      *
*          * 
*          *
  *      *
    ***
#include <iostream>
using namespace std;
//This Program was written by the programmer Ali Denno
void main()
{
	int x, i, j, b;
	for(x=1;x<=6;x++)
	{
		if(x==1 || x==6)
		{
			for(i=1;i<=7;i++)
			{
				if(i==3 || i==4 || i==5)
					cout<<"*";
				else
					cout<<" ";
			}
			cout<<endl;
		}
		else
			if(x==2||x==5)
			{
				for(j=1;j<=7;j++)
				{
					if(j==2||j==6)
						cout<<"*";
					else
						cout<<" ";
				}
				cout<<endl;
			}
			else
			{
				for(b=1;b<=7;b++)
				{
					if(b==1||b==7)
						cout<<"*";
					else
						cout<<" ";
				}
				cout<<endl;
			}
	}
}

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an empty square

#include <iostream>
using namespace std;
//This Program was written by the programmer Ali Denno
void main()
{
	int i, j, k;
	for(k=1;k<=6;k++)
	{
		if(k==1||k==6)
		{
			for(i=1;i<=6;i++)
				cout<<"*";
			    cout<<endl;
		}
		else
		{
			for(j=1;j<=6;j++) …
Salem commented: More clueless flogging a dead horse with code (untagged) -7