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Began Watching How to update qty into table2 from table1?
Hi. I am Sorry that I don't know how to ask question for my Scenario. Thats why I just used "How to update qty into table2 from table1? " This … -
Replied To a Post in How to update qty into table2 from table1?
I am consfused as you say you want to update table 2 from table 1 but your query that isn't working is updating table 1 from table 1. Please clarify … -
Replied To a Post in CSS Relative positioning preventing click on link
JorgeM - the point is that I DO want the links to work and they don't but I have sorted the problem now anyway -
Created CSS Relative positioning preventing click on link
Please look at my jsfiddle here - http://jsfiddle.net/ftuZ5/ . I know why the links won't work as the relative positioning I have used to create the link / menu backgrounds … -
Began Watching CSS Relative positioning preventing click on link
Please look at my jsfiddle here - http://jsfiddle.net/ftuZ5/ . I know why the links won't work as the relative positioning I have used to create the link / menu backgrounds … -
Replied To a Post in Unexpected $end in existing article template - error not previously there
I don't mean to sound rude but you really need to find a way to look through your code and find errors for yourself as that is all I am … -
Began Watching Unexpected $end in existing article template - error not previously there
Hi there, totally confused and hoping someone can help. I have an existing article template which suddenly developed this error when viewing the article: Parse error: syntax error, unexpected $end … -
Replied To a Post in Unexpected $end in existing article template - error not previously there
In lines 229 and 235 you have forgotten the `<?php endif; ?>` (added below) <div id="excerpt"> <div> <p><span id="label"><b>Excerpt:</b></span> <div style="float:left;"> <div><?php if(!empty($item->fields_by_id[32])):?><?php echo $item->fields_by_id[32]->result; ?><?php endif; ?></div> </div> </div> … -
Began Watching how to display the selected value of dropdown in php
$result123=mysql_query("select *from semdropdown"); <td><label for="textfield8">Semester </label></td> <td colspan="3"><select name="semester" value="<?php echo $semesterid; ?>"> <option value="">Select Semester</option> <?php while($row123 = mysql_fetch_array($result123)) { if($semesterid == $row123[semesterid]) { $selvar = "selected"; } echo … -
Replied To a Post in how to display the selected value of dropdown in php
Where is the value of $semesterid being set and why are you repeating the same code twice for your query and dropdown? -
Began Watching Create menu from MySQLI Using Array
Below are 2 functions that will handle the Query and rending of the menu from MySQL Database. This function Loops through the array. Takes in 2 arguments. function loop_section($array, $parent_id … -
Replied To a Post in Create menu from MySQLI Using Array
Well you will do as you are selecting all records and echoing them out through one loop all in the same unordered list. What exactly are you trying to do?
The End.