Posts by vinitmittal2008

Well as Narue suggested..
scanf function leaves '\n' into buffer, so when it reaches

while((character=getchar())!= '\n')

reads '\n' from buffer and loop terminates.
after this you are using

puts(sentence);

it will print some garbage value on screen bcoz your string is not terminated by a '\0' char.
to overcome these problems after using scanf function you need to flush input stream and after also terminate your string with '\0'.
Try this:

//Character Manipulation
#include <stdio.h>

void jsw_flush(FILE *in) // Function copied from older post of Narue
{
    int ch;

    do
        ch = getc(in);
    while (ch != '\n' && ch != EOF);

    clearerr(in);
}

int main()
{
int x;
//for loops
int counter=0;
//for input
char character;
char sentence[20];
printf("Press 1 to use getchar \n Press 2 to use gets \n Press 3 to use sscan \n ");
scanf("%d",&x);
jsw_flush(stdin); // flush input buffer
switch(x)
{
case 1:
    printf("Enter something\n");
    while((character=getchar())!= '\n')
    {
      sentence[counter++]=character;
    }
    sentence[counter] = '\0'; 
    puts(sentence);
    break; 

}


}

Exactly what are you trying to do??

For that you need a good knowledge of programming, like you need to know worst case complexity, best case complexity and Average time complexity.
Read This

Try this code..

# include <stdio.h>
# define MAX 100
int main(void)
{
    int oddcount, evencount;
    int array[MAX],i,n;

    printf("\n Enter Array Size (Between 1 to %d ): ",MAX);

    scanf("%d", &n); // User enters Array Size

    for(i = 0; i < n; i++)
    {
       printf("\n Enter %d value: ",i+1);
       scanf("%d", &array[i]); // Allows user to enter values into the Array
       }

    putchar('\n');
    printf("\nArray Values: ");
    for(i = 0; i < n; i++)
    {
       printf("\n [%d] value is %3d ", i+1, array[i]); //Prints out the array -- this is where program stops it should carry on down
    }
     //**************************************//
    oddcount = 0;
    evencount = 0;

     for (i = 0; i < n; i++) // Code determines wheter odd or even.

     {
          if (array[i] % 2 != 0)
          {
            //printf("\nThe number %d Is Odd.\n", i);
            oddcount ++;
          }

          else
          {
            //printf("\nThe number %d Is Even.\n",i);
            evencount ++;
          }
     }
     printf("\n Odd Num: %d \n Even Num: %d", oddcount , evencount );

     return 0;
}

If you are still getting some problem then post your problem here..

# include <stdio.h>
# define MAX 100
int main(void)
{
    int array[MAX],i,n;
    
    printf("\n Enter Array size (1 - %d):",MAX);
    
    scanf("%d", &n);
    
    for(i = 0; i < n; i++)
    {
       printf("\n Enter %d value :",i+1); 
       scanf("%d", &array[i]);
    }  
    
    // whatever else you want to do....... 

    return 1;
}

main function returns a integer vaule.. that is why return 1 is used.

Exactly what you want to do... if you just want to print * then it could be done by using a loop. scan a value from the user and run your loop like this..

int i,num;
// input a value here  from user in num..
for(i=1;i<=num;i++)
   putchar('*');

post your code here. We'll help you to solve your problem.

declare a int variable flag and you can try something like below code

for (ctr=0;ctr<as;ctr++)
{
  do{
   printf ("\nx[%d]= ", ctr);
   scanf ("%d", &x[ctr]);
   if(ctr>0)
   {
     for(j=0;j<ctr;j++)
     {
       if(x[j]==x[ctr])
        {
          flag=1;
          printf("\n Number Already Exist!,Enter Another Value\n");
          break;
        }
       else flag=0; 
     } 

   }
   else flag=0;
 }while(flag==1);
}

Try this one also..

# include <stdio.h>

int main(){
    int a=10,b=3,reminder;
    // suppose you want a%b.

     reminder = a -(a/b)*b;
     
     printf("\n\n  Reminder of %d/%d is %d",a,b,reminder);
     return 0;
   }

This will also work like % operator..

//Function Protoype
char* stringCat(char *pWord, char *pTemp);

//Function call in main
 stringCat(stringCat(word, ": "), temp);
   printf("\n\nConcatenation: \"%s\".", word);
   printf("\n\n");

//Actual Function
char* stringCat(char *pWord, char *pTemp)
{ 
   int i;   
   int j;
   
   for (i = 0; pWord[i] != '\0'; i++);    // Notice the ;
   for (j = 0; pTemp[j] != '\0'; j++)
      pWord[i+j] = pTemp[j];
   pWord[i+j] = '\0';
   
   return pWord;
}

If Above is your question then the code could be...

#include <stdlib.h>
#include <stdio.h>

int main ()

{
    int Tab[5][3], i, j, GrandA = 0, GrandB = 0, GrandC = 0;
    int index_a=0,index_b=0,index_c=0,big_a,big_b,big_c;

    for(i = 0; i < 3; i++)
    {
        for(j = 0; j < 5; j++)
        {
            scanf("%d", &Tab[j][i]);
        }
    }

    printf("\n\n");

    for(i = 0; i < 3; i++)
    {
        for(j = 0; j < 5; j++)
        {
            printf("%d\t", Tab[j][i]);
        }
        printf("\n");
    }

    for(i = 0; i < 3; i++)
    {
        printf("\n");
        big_a = 0;
        big_b = 0;
        big_c = 0;
        
        for(j = 0; j < 5; j++)
        {
            if(big_a < Tab[j][0])
            {
                big_a = Tab[j][0];
                index_a=j;
            }

            if(big_b < Tab[j][1])
            {
                big_b = Tab[j][1];
                index_b=j;
                
            }
            if(big_c < Tab[j][2])
            {
                big_c = Tab[j][2];
                index_c=j;
            }
         }
        GrandA +=big_a;
        GrandB +=big_b;
        GrandC +=big_c;
        Tab[index_a][0]=Tab[index_b][1]=Tab[index_c][2]=0;
   
    }
    printf("%d ", GrandA);
    printf("%d ", GrandB);
    printf("%d ", GrandC);

 return 0; 
}

If its not your question then please describe it with example...

Just learn the use of strcpy, strcat and itoa function.. and it would be quite easy to implement such code..:)

Have a Look..

# include <stdio.h>
# include <string.h>
# include <stdlib.h>
int main()
{
 char fname[12];
 char num[3]={"00"};
 int i;
 for(i=1;i<=20;i++)
  {
   strcpy(fname,"data-");
   if(i<10)
   itoa(i,&num[1],10);
   else
   itoa(i,num,10);
   strcat(fname,num);
   strcat(fname,".txt");
   puts(fname);

 }

 return 1;
}

Thanks for the suggestion... well now i tried this..

# include <stdio.h>

void show(int (*)[3],int,int);

int main()
{
  int a[3][3]={1,2,3,
	       4,5,6,
	       7,8,9};

  show(a,3,3);
  return(0);
}
void show(int (*p)[3],int row,int col)
{
  int i,j;
  printf("\n\n\n");
  for(i=0;i<row;i++)
   {
     for(j=0;j<col;j++)
	printf("\t %d",p[i][j]);
     printf("\n");
   }
}

Is it right way??