how to solve the reccurance relation given below
T(n)=T(n+1)+1,given that T(1)=1
satishvengala 0 Newbie Poster
sarehu 84 Posting Whiz in Training
Well, for that, you could just plug in values of n such as -5 and -7 and notice a pattern.
satishvengala 0 Newbie Poster
but the examinar given options like below
1.O(square of n)
2.O(n)
3.O(1)
4.theata of square of n
lulusweety 0 Newbie Poster
If we use substitution method, finding T(n) for different values of n with boundary condition
T(1)=1, We obtain arelation of the form T(n)=-n+2, which can be written as O(n). Is it right?
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