binary to decimal and decimal to binary functions

Sinaru 1 184 Views

I wrote this code for fun. Wanted to do such a thing so that I would be able to use this in the future. I'm kinda new to this forum. I like to know what you think about the code. If can point out some mistakes or ways to improve the code, it would be great.. :)

The ICE Man commented: Well Done :) +0 
#include <iostream>
#include <math.h>
using namespace std;

/* The following function coverts a binary value to an int value. You have to
 * input the binary value as a string to this function and then it will output
 * the int number of it. Characters other than 0 will treat as a 1 or true.
 */
int bin2dec(string binVal)
{
    int total = 0;
    int i=0;
    int length = binVal.length();
    int isMinus= false;

    if(binVal[0] == '-')
    {
        isMinus = true;
        length--;
        for(i=0; i<length;i++)
        {
            binVal[i] = binVal[i+1];
        }
    }

    for (i=0; i < length; i++)
    {

        if (binVal[length - (i + 1)] != '0')
            total = total + pow(2, i);
    }

    if(isMinus)
        total = total * (-1);

    return total;
}

/* The Following function can be used to convert an integral value to binary.
 * Provide the integral value to this function and it will output the related
 * binary value in a string format.
 */
string dec2bin(int decVal)
{
    string value = "";

    bool isMinus = false;

    if (decVal < 0)
    {
        isMinus = true;
        decVal = decVal * (-1);
    }

    while (decVal > 0)
    {
        if (decVal % 2)
            value = '1' + value;
        else
            value = '0' + value;

        decVal = decVal / 2;
    }

    if (isMinus)
        value = '-' + value;

    return value;
Member Avatar for scott_dabas
scott_dabas -2 Newbie Poster

code is good but for decimal to binary conversion, it can get even better ........ multiply the remainders with powers of 10 from 0 onwards ....after dividing the dec number by 2 like we do while converting binary to dec.
the code gets even simpler for dec to binary conversion.

Member Avatar for mbulow
mbulow 10 Junior Poster in Training

Hi Sinaru :-)

Since I don't know how familiar you are with stuff like this I have too ask:

You represent a negative binary number as a positive binary number prefixed with a '-'. Is that your own intentional design or because you do not know the real way to represent negative numbers?

Member Avatar for Sinaru
Sinaru

Sorry for the delayed answer. I'm currently working on our final software project for the HND.

@mbulow: I used the - sign so that the common users would understand that it's a negative value. I didn't try to convert it into the way that computers hold the negative values.

@scott: Thnx for the info.. I will see about that.. :)

BTW I found a bug when converting dec2bin. That is if you password 0 as the integer value, the return value will be nothing. So I used another (else)if statement before the while loop to see if the int value is 0 and if it is then returns 0... :P

Member Avatar for mrnutty
mrnutty 761 Senior Poster

Here is a way to do it using metaprograming. That way you get the result before you
even start the program.

#include <iostream>


template<int binarySequence>
struct Binary{
	enum{ result = Binary<binarySequence/10>::result << 1 | binarySequence % 10 };
};
template<>
struct Binary<0>{
	enum{ result = 0 };
};

int main(){		
	using namespace std;
	cout << Binary<1>::result << endl; // outputs 2^0
	cout << Binary<10>::result << endl; // outputs 2^1
	cout << Binary<100>::result << endl; // outputs 2^2
	cout << Binary<1000>::result << endl; // outputs 2^3
	cout << Binary<10000>::result << endl; // outputs 2^4
	cout << Binary<10100>::result << endl; // outputs 20

}

I admit, that the formula used is not credited to me. Although the above works.
It does not have a error checking, for input that does not consists of 1's and 0's.

Isn't this so cool? You get the answer before you even run your program!

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