Random Character Generator Help

[owen99]

hi can anyone help me i am trying to get a random character generator which generates 10 characters in ASCII range and then cast them into characters

heres my code but its not working. it says error C2440: '<function-style-cast>' : cannot convert from 'std::string' to 'char'

heres my code

#include <iostream>
#include <cstdlib>
#include <ctime>
#include <string>


using namespace std;

int main()

{
	string RandNum; // name of the string
	char UserLetter; // what the user will enter  and the place of storage in char


	for (int i(0); i !=10; i++) // a for loop which will run until the game has 10 letters
	{
	srand ((unsigned) time(0) ); 
	
	RandNum = 65 + rand()% 26; // generate the numbers in the ASCII range

	}


	cout << (char)RandNum << endl; // casting them into characters
	return 0;
}

any help will be greatly appreciated

[VernonDozier]

You can't cast a string to a char, which is what you are trying to do in line 25. That's where the error is coming from.

Also, your line:

RandNum = 65 + rand()% 26; // generate the numbers in the ASCII range

is assigning a value from 65 to 90 to a string. You should replace RandNum in this line with a variable that is a character variable.

[ShawnCplus]

#include <iostream>
#include <cstdlib>
#include <ctime>
#include <string>


using namespace std;

int main()

{
        srand ((unsigned) time(0) ); //<----Only seed once	
//A string is not necessary, you aren't using any the facilities of the class
        char* RandNum;
//What is this supposed to do? There's no input from the user?	
        char UserLetter; // what the user will enter  and the place of storage in char


	for (int i=0; i <10; i++)	
	     RandNum[i] = 65 + rand()% 26;

	cout << RandNum << endl;
	return 0;
}

There is no need to cast a string to a char* anyway since cout already knows what a string is and can output it just fine

[yangclan]

can anyone help me, what if i want to random only vowel (a,e,i,o,u) ?thz

[NathanOliver]

for a set of random letters like only vowels you can create an array that holds the vowels and then use rand % (size of array) to get the index for the element in the vowel array.

[yangclan]

oh i got it....thank.

[nbaztec]

oh i got it....thank.

In that case mark this thread as solve, please.

[mrnutty]

#include <iostream>
#include <cstdlib>
#include <ctime>
#include <string>


using namespace std;

int main()

{
        srand ((unsigned) time(0) ); //<----Only seed once	
//A string is not necessary, you aren't using any the facilities of the class
        char* RandNum;
//What is this supposed to do? There's no input from the user?	
        char UserLetter; // what the user will enter  and the place of storage in char


	for (int i=0; i <10; i++)	
	     RandNum[i] = 65 + rand()% 26;

	cout << RandNum << endl;
	return 0;
}

There is no need to cast a string to a char* anyway since cout already knows what a string is and can output it just fine

really, I mean come on. RandNum is never allocated, but still written into. Plus its
not null-terminated. And on top of that you tell him not to use std::string, SMH.

Even though, he might not need to use string's capability now, he might later on. And
at the very least, he does not have to worry about dynamic memory management.

[NathanOliver]

Hey guys not sure if you realize but this thread was resurrected by yangclan. I didn't notice until he replied back that he had bumped a dead thread.

[Anilorap]

Can someone explain a little bit more about the random letter generator.. please I need help on that.