Hi.I want to thank in advance for all replys.
Well let's get to the problem.
I need to a C++ code that will do the following:
1.User inputs a number
2.All digits of the number inputed not divisable by 2(odd numbers) must be multiplicated. (* operation ).
3.Show multiplication result.
Please give a reply till tomorrow.
Do you have anything as an attempt? It's fairly simple logic, I believe. Get the value of the input, assign it to a variable. Test to see if variable % 2 != 0. If true, then multiply, else ... whatever else u want to do to it... return... or whatever...
Do you have anything as an attempt? It's fairly simple logic, I believe. Get the value of the input, assign it to a variable. Test to see if variable % 2 != 0. If true, then multiply, else ... whatever else u want to do to it... return... or whatever...
i need to multiply the digits of the number that are dividable by 2.
Example :if the number is 257685 then :2*6*8=96
I don't know the algorithm of finding every number's digit.
i need to multiply the digits of the number that are dividable by 2.
Example :if the number is 257685 then :2*6*8=96
I don't know the algorithm of finding every number's digit.
I am assuming u want this:
given number x= 257685
u want to find the digits in separate way
like: i1=2, i2=5, i3=7, i4=6, i5= 8, i6=5
Here is my suggestion:
divide by 10, store the number, and continue dividing by 10
unless u hit upon zero.
like-> 257685/10 ->25768
25768/10 -> 2576
2576/10 -> 257
257/10-> 25
25/10 -> 2 <---- this is ur first digit.
any futher division will result zero
Now compare if that number i even or odd as required by ur task
and continue this process still u exhauste the set.
Hope it helps. :)
Hi.I want to thank in advance for all replys.
Well let's get to the problem.
I need to a C++ code that will do the following:
1.User inputs a number
2.All digits of the number inputed not divisable by 2(odd numbers) must be multiplicated. (* operation ).
3.Show multiplication result.Please give a reply till tomorrow.
We don't do homework for people here. Try it out yourself and post up your code if you encounter any problems.
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