creating "FOR LOOP"

[king_786]

hello i am stuk on this piece of work which i have no understaning at all!!! this is the question could someone please show me or give me gudlines in how to do it!!!

Write a Java application that asks a user for their name and displays it in a ‘box’ similar to that you implemented in week 1, exercise 1. For this application, you use a for loop to repeated printing * and space characters to result in the boundaries and padding, respectively. Below is what your application should produce.

Please enter your name> king 786

/********\
| |
| king 786 |
| |
\********/

The number of characters (* or space) is determined by the length of the name entered (hint: use String length method). Remember that you have to add 2 to this length in order to take into account the space either side of the name.

[tux4life]

Example of a For-loop:

for(int i = 0; i < 3; i++)
{
    /* This loop will repeat 3 times */
}

[king_786]

but how do i incorporate this in to the scenario???

[javaAddict]

Obviously instead of 3 you will have the number of '*' you want to print.
And in the for-loop use the method:

System.out.print("");

The above method doesn't change line.
Of course when the loop is done remember to call the one that changes line in order to continue writing at the next line.

Also you can call this with no arguments:

System.out.println();

[javaAddict]

WHY did you double post?

http://www.daniweb.com/forums/thread184806.html

[BestJewSinceJC]

And your teacher is trying to tell you that the String's length method will tell you how long their name is. So what everyone else here has said applies, let me put it all together for you:

1. Prompt the user, asking them what their name is
2. Use a Scanner Object and the readLine method to read their name into a String
3. use the length() method of the String class to figure out how long their name is. Lets call this "nameLength"
4. Use a for loop to print out the *'s. Inside the for loop, have an if statement that says for (int i = 0; i < nameLength; i++){
//print the *'s and other stuff in here
}

[javaAddict]

The number of characters (* or space) is determined by the length of the name entered (hint: use String length method). Remember that you have to add 2 to this length in order to take into account the space either side of the name.

Also don't forget to add 2 as stated above, and you will need to play with the methods:

System.out.println();
System.out.print();

As I said, one changes line the other doesn't. So decide which one goes inside the loop and which doesn't in order to have this result:

/***********\

[king_786]

buh i have no idea in how 2 do this??

[javaAddict]

buh i have no idea in how 2 do this??

We can only show you the door; you are the one that has to go through it

Meaning that we have already told you which methods to use and how. You need to think the way. You already know the commands. Only the System.out. ..... and the for-loop which was explained are needed. Coding it is easy. But you need to think how to use the commands, we cannot post the solution, just use the command to print what is required.

Also, at first if you don't know how to read the input try using the:
> argument array of the main:
> public static void main (String [] args)

Or put a value to a variable and try work with it

[Superstar288]

Alot of information has been given and you should be able to get it working. just do some trial and error that is the best way with programming.

also you can use
BufferedReader to get the users input that is how we were taught at uni.
check the internet there are lots of examples for it. please let us know how you get on

[javaAddict]

Alot of information has been given and you should be able to get it working. just do some trial and error that is the best way with programming.

also you can use
BufferedReader to get the users input that is how we were taught at uni.
check the internet there are lots of examples for it. please let us know how you get on

I believe that his problem is printing what is asked based on the "name" input. Trying to get the "name" input using BufferedReader will not help much since he cannot do the simpler things.

So I suggest first to try to get the program work with some fixed value and then decide how to get the input