i want to print the double base representation of a number
ie if my number is 38 i shud get 36 + 2 and for 655 i shud get 648 + 6 + 1.
here's my code:
unsigned long bs(unsigned long a[],unsigned long d, unsigned long beg, unsigned long end, unsigned long x)
{
int mid;
mid=(beg+end)/2;
if (x<a[mid])
{
end=mid-1;
bs(a,d,beg,end,x);
}
else if(x<a[mid])
{
beg=mid+1;
bs(a,d,beg,end,x);
}
else if(x>a[end])
{ cout<<a[end]<<" + ";
return a[end];
}
else if(x==a[mid])
{
cout<<"FOUND!!\n";
return a[mid];
}
}
void alg(unsigned long a[],unsigned long d, unsigned long x)
{
unsigned long num;
num=(x-bs(a,d,0,30,x));
if (num>0)
alg(a,d,num);
}
main()
{
int c,n,d;
d=c=(unsigned long)(pow(32,2));
unsigned long a[d],b[c],t,x,y;
d=c=0;
a[0]=0;
b[0]=0;
for(int i=0;i<32;i++)
{
for(int j=0;j<32;j++)
{
b[c]=(unsigned long)(pow(2,i)*pow(3,j));
if(j==0 || ULONG_MAX/pow(3,j)>pow(2,i))
{
a[++d]=b[c++];
// cout<<i<<"\t"<<j<<"\t"<<a[d]<<endl;
}
else
{
break;
}
}
}
sort(a,a+d);
cout<<"enter element:";
cin>>x;
cout<<"its representation is :"<<endl;
alg(a,d,x);
system("PAUSE");
}wat im doing in my code for alg() is im finding the element in the array using bs()
if the elemnt i want is in the array im printing that otherwise im finding the element that is closest (from the lesser side) to it and finding the difference ie (x - closest number to x) and calling alg for the difference and so on.
ie for 655 the closest elemnt is 648 and 655-648 is 7 , calling alg with 7 gives the closest elemnt as 6 n 7-6 is 1 n so on..
in my bs() code im returning the elemnt or the one which is closest to it. but somehow its not printing that elemnt n neither is it returning it.
please help...
thanks for reading!