Hi, I'm working on a program to convert Celsius to Fahrenheit, but I have a problem when I run a check to make sure that input is not a letter. My problem is that if the user inputs a 0 it catches it with the
if(num == 0) {
cout << "That was not a number!\n\n";
}So I tried changing it to this:
if(num == 0 && !(buf == "0")) {
cout << "That was not a number!\n\n";
}but it still doesn't work, even when 0 is the only thing submitted! Any suggestions?
I think that it might be registering the enter as part of the string, but any advice to help this to work, or any advice on how this could be done better would be appreciated!
Below is my entire code.
// enter the temperature in celsius
int nCelsius;
int nIsANumber;
char buf[256];
nCelsius = 0;
nIsANumber = 0;
while(nIsANumber == 0)
{
// Ask for input here
cout << "Enter the temperature in Celsius: \n";
cin.getline(buf,256);
int num = atoi(buf); // atoi returns 0 if it is invalid
if(num == 0 && !(buf == "0")) {
cout << "That was not a number!\n\n";
}
else {
nCelsius = atoi(buf);
nIsANumber = 1;
}
}
//Conversion factor for celsius to fahrenheit
int nFactor;
nFactor = 212 - 32;
int nFahrenheit;
nFahrenheit = nFactor * nCelsius/100 + 32;
//output the results
cout << "Fahrenheit temperature is:";
cout << nFahrenheit;
nCelsius = 0;
