what is wrong in this programm it didn't work

[ahmed hefnawy]

#include"stdio.h"
#include"string.h"
#include"math.h"
#include"stdlib.h"
void convlute(char s1[20],char s2[20])
{
	int i,p=0,t=0;
	char s3[20];
	for(i=0;i<20;i++)
	{
		if(s1[i]!='+'&&s1[i]!='-'&&s1[i]!='*'&&s1[i]!='/'&&s1[i]!='('&&s1[i]!=')')
		{
			s2[p]=s1[i];
			p++;
		}
		else if(s1[i]='(')
		{
			t++;
		}
				else if(s1[i]=='+'||s1[i]=='-')
		{
			if(s3[t]=='*'||s3[t]=='/')
			{
				s2[p]=s3[t];
				s3[t]=s1[i];
				t++;
				p++;
			}
			else 
			{
				s3[t]=s1[i];
				t++;
			}
		}
		else if(s1[i]=='*'||s1[i]=='/')
		{
			s2[p]=s1[i];
			p++;
		}
		else if(s1[i]==')')
		{
			do
			{
			s2[p++]=s3[t--];
			}
			while(s3[t]!='(');
		}
	}
}
void main()
{
	char x[20],y[20];
	int i;
	for(i=0;i<20;i++)
		scanf("%c",&x[i]);
	for(i=0;i<20;i++)
		y[i]=0;
	convlute(x[20],y[20]);
	printf("%s",y);
}

[Fbody]

"It doesn't work" isn't going to cut it. Give us some specifics.

Also, use code tags

[ahmed hefnawy]

it's a programm that include operatins of : ( ) + - * / and user makes what he want like :(3+8)/(5*6-2)

[ahmed hefnawy]

sorry (3+8)/(5*6-2)

[Fbody]

The info helps, but that's not what I mean by specifics... What are the errors?

[ahmed hefnawy]

ok when i try it the programm must take the 20 of the array ok
then it must give us the results..it didnot it stoped at
if(s1!='+'&&s1!='-'&&s1!='*'&&s1!='/'&&s1!='('&&s1!=')')
i want to know why
plz try it and tell me if my info doesn't satisfy u

[abhimanipal]

You are passing both the array by value (syntax for this is also wrong). Change this to pass by pointer

There are more serious bugs ... Will try to get back to you in some time on those

[ahmed hefnawy]

i know there r bugs but where it is

[abhimanipal]

Is this what you are trying to do ?
Evaluate an infix expression like (3+5)/(2+2)

You will have to convert it to post fix and then evaluate the postfix expression
http://www.google.com/search?hl=en&q=evaluating+infix+expression&sourceid=navclient-ff&rlz=1B3GGGL_enIN258IN259&ie=UTF-8