I'm trying to print an array of 3x3 and placing random numbers within them that has no repetition. I think what I did was right but there just isn't any output. I know I can easily get the answer somewhere but I would like to know what is wrong with my code. Can anyone help me? Sorry if it is hard to read my code.

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main(void)
{
    int i,j,k,l;            //loop initilizers
    int count;              //to check for repetition
    int num;
    int grid[3][3] = {};

    srand(time(NULL));

    num = 1 + rand()%9;
    
    //generating the array & checking for repetition
    for(i=1;i=3;i++)        
    {
        for(j=1;j=3;j++)
        {
            for(k=1;k=3;k++)        //checking the row for repetition
            {
                if(grid[k][j]=num)
                count++;
            }

            for(l=1;l=3;l++)        //checking the column for repetition
            {
                if(grid[i][l]=num)
                count++;
            }

            if(count<1)
            {                //if number isn't found in either row or column,
            grid[i][j]=num; //set the number into array
            }
            else
            {
            grid[i][j]=10;
            }
        }
    }

	for(i=1; i=3; i++)      //printing the array
	{
		for(j=0; j=3; j++)
        printf("%d ", grid[i][j]);

	}
    return 0;
}

You have = instead of == in your if statements.

You only ever call rand() once.

You never initialise count.

Hmm, I changed all the = in the if statements to == , placed the rand() inside for(j=1;j=3;j++) loop and initialized count to 0.

But it still doesn't work? (Btw, I've initialized it but forgot to post the updated code here earlier)

The loop for( i = 1; i == 3; i++ ) never does anything.

That loop says, in English, "Start i at 1. As long as i is equal to 3, do the loop and increment i."

i doesn't start out equal to three. You need the condition to be i < 3. See how that works for you and move forward from there.

There are many more mistakes in your code...

1. When you are accessing the matrix elements the for loops should be

for(i=0;i<3;i++)
{
       for(j=0;j<3;j++)
        {
               // Do printing checking what ever 
         }
}

2. Initialize count to -1
3. When you are checking for repetition, you have to use == to =
4. I dont think the logic you have used for checking repetition is correct as well. What I would do would be after inputting the number use the loops I have described above to check each entry of the matrix, to see if the input exists there or not
5. Why are you modding the random number by 9 ? I get it that you need 9 entries, but that does not mean all entries have to be smaller than 9. What you want to do is call rand 9 times instead.

The loop for( i = 1; i == 3; i++ ) never does anything.

That loop says, in English, "Start i at 1. As long as i is equal to 3, do the loop and increment i."

i doesn't start out equal to three. You need the condition to be i < 3. See how that works for you and move forward from there.

Wow, what a serious mistake that I made. Thanks for pointing it out. :)

There are many more mistakes in your code...

1. When you are accessing the matrix elements the for loops should be

for(i=0;i<3;i++)
{
       for(j=0;j<3;j++)
        {
               // Do printing checking what ever 
         }
}

2. Initialize count to -1
3. When you are checking for repetition, you have to use == to =
4. I dont think the logic you have used for checking repetition is correct as well. What I would do would be after inputting the number use the loops I have described above to check each entry of the matrix, to see if the input exists there or not
5. Why are you modding the random number by 9 ? I get it that you need 9 entries, but that does not mean all entries have to be smaller than 9. What you want to do is call rand 9 times instead.

1. Thanks, not sure why that didn't hit me earlier.
2. Sorry to ask but why initialize it to -1?
3. Fixed that based on the earlier post. :)
4. Isn't it the same as the first question? Still, thanks.
5. I'm doing so because I need the random number to be a number from 1 to 9.

Anyway, I've updated my code but still it doesn't check for repetition? Any help will be appreciated.

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main(void)
{
    int i,j,k,l;            //loop initilizers
    int count =-1;              //to check for repetition
    int num;
    int grid[3][3] = {};

    srand(time(NULL));

    //generating the array & checking for repetition
    for(i=1;i<=3;i++)
    {
        for(j=1;j<=3;j++)
        {
            num = 1 + rand()%9;
            grid[i][j] = num;

            for(k=1;k<=3;k++)
            {
                for(l=1;l<=3;l++)        //checking the column for repetition
                {
                if(grid[k][l]==num)
                count++;
                }
            }

            if(count<=0)
            {                //if number isn't found in either row or column,
            grid[i][j]=num; //set the number into array
            count = -1;
            }
            else
            {
            printf("repeated number = %d\n",num);
            grid[i][j]=-1;
            }
        }
    }


	for(i=1; i<=3; i++)      //printing the array
	{
		for(j=1; j<=3; j++)
        printf("%d ", grid[i][j]);

	}
    return 0;
}
for(i=1;i<=3;i++)
    {
        for(j=1;j<=3;j++)
        {
            num = 1 + rand()%9;
            grid[i][j] = num;

Nop that is an out of bounds data access, undefined behaviour and asking for a crash.

You did not read post #5 by abhimanipal closely enough.

Arrays are indexed from 0 if you declare an array with a size of 3, then valid indexes are 0, 1, 2

int array[3] = {};
int a;

a = array[0]; // Good
a = array[1]; // Good
a = array[2]; // Good
a = array[3]; // Bad - out of bounds access

if you can guarantee non-repetition, then your numbers aren't random.

statement 20 is unnecessary.
You are anyway setting/ ignoring the value of num in the if else block.

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