counting int program help!!!

[kerek2]

Hi all... i need to do some study regarding how to count the multiple int that keep in by user like this :-

"Please enter the integer :
1
3
5
66
88

(1+3=4+5=9+66=75+88=163 - the program will terminted cause exceed than 100)

how to do ?...i stuck very long here...below is the coding that i make;;hope u will help me;;;

import java.io.*;
 import java.util.Scanner; 
 
 
 public class Soalan1
 {
 	 public static void main ( String [] args ) throws IOException   //throw any exceptions
     {
          
          
          
          
          BufferedReader stdin =  new BufferedReader( new InputStreamReader( System.in ) );

            //note the previous line. you can write the statements 2 and 3 in a single line
            // 2&3. Create a single shared BufferedReader for keyboard input.
            int a,n, sum;
            
            sum = 0;

             System.out.println( "KEEP IN THE INTEGER ! " );
             while (true)
		{
			
						
	 Scanner scan = new Scanner(System.in); 
			
        n = scan.nextInt(); 
 sum = sum + n;


			if (sum  >= 100)
			{
			
			// n is zero, so break out of the enclosing while loop
				break;
				
	
			
			}//end if
			
	}//end while
			
			
	

          System.out.println(execeed 100 =  "+ sum +" )");
//		   System.out.printf( "Sum is %d\n", sum ); // display sum 
//
		

      }               // end main method

}                     // end class calc

[stephen84s]

Well you have not mentioned the problem and just visually going through the code, I am guessing its a compile error caused by a missing double quote on line 47:

System.out.println(execeed 100 =  "+ sum +" )");

Should be:-

System.out.println("execeed 100 =  "+ sum +" )");

[kerek2]

Bro.... i need to display result of sum int by int that keep in by user....right now i just can display all sum...what i need is output like this.....

"( 1+3=4+5=9+66=75+88=163 - the program will terminted cause exceed than 100)

how to do..plz help me...

[musthafa.aj]

stephen is correct..

this is simple problem to solve...

[stephen84s]

Bro.... i need to display result of sum int by int that keep in by user....right now i just can display all sum...what i need is output like this.....

"( 1+3=4+5=9+66=75+88=163 - the program will terminted cause exceed than 100)

how to do..plz help me...

Use an Array to store the numbers keyed in by the User.

[musthafa.aj]

it is better to append all integer in stringbuffer while getting as input like this.

stringbuffer sb=new stringbuffer();

sb.append(firstinput+"+");
.
.
.
.
sb.append("="+total);

then convert stringbuffer into string like sb.tostring and display that string..

sys.out.print("the program termintaed because"+sb.toString);

[kerek2]

how to use array to store user input bro?....

[stephen84s]

how to use array to store user input bro?....

My Post had a link on how to use Arrays:-
http://download.oracle.com/docs/cd/E17409_01/javase/tutorial/java/nutsandbolts/arrays.html

Even musthafa's solution is a good option, although I would suggest using a StringBuilder as opposed to StringBuffer.

[kerek2]

mmm...still stuck lor......can u guide me to use array ?

[stephen84s]

mmm...still stuck lor......can u guide me to use array ?

Post the code that you have tried.

[kerek2]

as above lor....

[kerek2]

import java.io.*;
 import java.util.Scanner; 
 
 
 public class Soalan1
 {
 	 public static void main ( String [] args ) throws IOException   //throw any exceptions
     {
          
          
          
          
          BufferedReader stdin =  new BufferedReader( new InputStreamReader( System.in ) );

            //note the previous line. you can write the statements 2 and 3 in a single line
            // 2&3. Create a single shared BufferedReader for keyboard input.
            int a,n, sum;
            
            final int MAX=100;
            
            sum = 0;

             System.out.println( "INSERT INTEGER ! " );
             
             
             
			 
             
             
             
             
             
             while (true)
		{
			
		//	Pembaca read = new Pembaca();
			
	 Scanner scan = new Scanner(System.in); 
			
        n = scan.nextInt(); 

          //  String input = stdin.readLine();

           // int i = Integer.parseInt( input );
           
            
           
            
          //  n = read.bacaInt();
            
            
           sum = sum + n;

  
//if (n <=100)
//{
	 
//}
           // n++;

			
			
	//		System.out.println("The total of the numbers is:" + sum);


			if (sum  >= 100)
			{
			
				// n is zero, so break out of the enclosing while loop
				break;
				
	
			
			}//end if
				
			
		//	System.out.println( sum );
		//	if (n <=100)
		//	{
		//	  System.out.print(n);
	      //  	System.out.print(" + ");
	        // 	System.out.print(n);
	         //	System.out.print(" = ");
	       //  System.out.println(  sum );
		//	}
		// print out their sum
	//	System.out.print(sum);
	//	System.out.print(" + ");
	//	System.out.print(n);
	//	System.out.print(" = ");
	//	System.out.println( +sum );
		//	sum = sum + n;
		

		// and report our results
		
		
	
			
			}//end while
			
			
	

          System.out.println("("+sum+ " exceed 100  =  "+ sum +" terminated)");
//		   System.out.printf( "Sum is %d\n", sum ); // display sum 
//
		

      }               // end main method

}                     // end class calc

Help me plz...

i need to display like this ( user input + n+ n+n+n+n+n=sum - terminated exceed 100)

[stephen84s]

I gave you a link on how to use arrays, similarly mustafa gave another solution, I dont see you having tried any of them, If you dont try any of the solutions, how can we help ???