how can i get the index number of a iterator? for instance:
i wante to return the number of times ive gone through the loop.
list = [(mark, jacky,jane),(stick,cheri,nice),(elly,younces,pluto)]
for i in list:
print ithis returns lists. but i want an output like:
>>1
>>2
>>3how do i do this withought making another variable and adding to it for each iteration through the loop.
also: is there a similar expression like C's" index++ " for python.
Hi!
lst = ["a","b","c"]
# the old method
for i in range(len(lst)):
print i, lst[i]
# the new one (since Python 2.4)
for i, x in enumerate(lst):
print i, xalso: is there a similar expression like C's" index++ " for python.
No.
Regards, mawe
wonderful. thx
There is a discussion of how C and Python handle integers, and explains why n++ does not make sense in Python. See:
http://www.daniweb.com/tutorials/tutorial32575.html
Editor's note: this tutorial has been send to the doghouse as utter kaka junk!
In your corrected code this would work fine ...
list = [('mark', 'jacky','jane'),('stick','cheri','nice'),('elly','younces','pluto')]
n = 0
for i in list:
print n, i
n += 1 # replaces C's n++If you want to pick the list of tuples really appart, then use this ...
list = [('mark', 'jacky','jane'),('stick','cheri','nice'),('elly','younces','pluto')]
n = 0
for t in list:
m = 0
for i in t:
print n, m, i
m += 1
n += 1
"""
0 0 mark
0 1 jacky
0 2 jane
1 0 stick
1 1 cheri
1 2 nice
2 0 elly
2 1 younces
2 2 pluto
"""This gives you the index of the tuple, followed by the index in the tuple, then the value.
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