Process.Start(Path.GetDirectoryName(xsM))
xsM = String
with a FullPath
of a .File.
.i would like to load win.explorer with that.File.Selected=True
.
.thanx.in.advance.
Process.Start(Path.GetDirectoryName(xsM))
xsM = String
with a FullPath
of a .File.
.i would like to load win.explorer with that.File.Selected=True
.
.thanx.in.advance.
Here is what you might be looking for:
Dim filePath As String = "C:\Users\%USERNAME%\Documents\test.txt" 'Example file
Process.Start("explorer.exe", "/select," & filePath) 'Starts explorer.exe and selects desired file
Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments) & "\test.txt" 'Example file
seems to work a little better than "C:\Users\%USERNAME%\Documents\test.txt"
; += thanks. :)
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