i got a string
var=96.33% from 120
how do i get 96.33 from $var?
Regex!
Try something like this:
var='96.33% from 120'
decimal=$(echo $var|grep -Eo '[0-9]*\.[0-9]*')
echo $decimal
I hope this helps!
-G
hi,
$ var="96.33% from 120"
$ echo "${var%\%*}"
96.33
this is POSIX parameter expansion.
as you see, as %
is a special character for Parameter Expansion (see man bash), so it has to be protected.
it works,
and now, i want to make a calculation by using the decimal
for instance:
`expr $decimal + 1`
how do i do that?
shells can't do float numbers arithmetic evaluation. expr
(that is an external command) can't either.
you'll have to use bc
echo "$decimal + 1" | bc -l
or with bash
bc -l <<<"$decimal + 1"
it works,
and now, i want to make a calculation by using the decimal
for instance:
`expr $decimal + 1`
how do i do that?
it works,
I appreciate all your help
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