#include<iostream>
using namespace std;
int main(){
int fish =6;
int * fishp = &fish;
cout<<fishp<<endl;
return 0;}
this runs ok, but i get the same memory address when i cout either fishp or &fishp. how is it possible for a pointer to
have the same address as the address it's pointing to?
Maybe you did something wrong. This is what I get
00AFFF10 00AFFF04
Press any key to continue . . .
#include<iostream>
using namespace std;
int main(){
int fish = 6;
int * fishp = &fish;
cout << fishp << ' ' << &fishp << endl;
return 0;
}
Are you trying to do this? cout << fishp << ' ' << &fish << endl;
Then yes, they will both be the same because fishp points to &fish.
no please, that wasn't the intention.. i wanted the memory address of the variable fish, and that of the pointer fishp. but thanx a lot :)
also, i didn't print both out at the same time.. i run it the first time to cout fishp, then changed the program and run it again to cout &fishp and they all gave same memory address; but if i print both out at the same time, i get different 0x figures
What compiler are you using? I tried that and got two different addresses.
but i get the same memory address when i cout either fishp or &fishp.
Not possible.
if you use cout<<fishp then it print the address of the variable , it points to(therefore print the address of fish).
when you use cout<<&fishp then it print the address of the variable(fishp) itself.
therefore two differents addresses will be printed.
ok thanks :)
I use code blocks
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