MPH conversion to minutes & seconds . . .

[aegugka]

I'm working on a C++ program to convert MPH to minutes and seconds.

I'm stuck.

This is my code so far.

It runs, but when I key a value (i.e. 6.5), the program crashes and stalls.

What I am overlooking?

[aegugka]

Here is the code.



#include <iostream>
using namespace std;

int main()
{
    int miles_per_hour, mins, secs, M, Y;
    {
        cout << "What is the miles per hour? ";
        cin >> miles_per_hour;
    }
        M = miles_per_hour;
        Y = (1 / 60) * M;
        mins = (int)(1 / Y);
        secs = (int)((1 / Y) - M * 60);
    {
        cout << "The pace is " << mins << "minutes" << "and" << secs << "seconds";
    }
    return 0;
}

[Hiroshe]

Welp. An int can only hold integers. So, can you guess what happens when Y = (1 / 60) * M runs? What about lines 17 and 18.

Use doubles instead, and see what happens.

[aegugka]

I apologize. I'm new to coding.

I changed it to double mins, sec, M, Y

When I debug, it appears to run asks me to input (I key 6.5), but after that it ends with no output.

[aegugka]

Asides from using double, how does the rest of the code look?

[aegugka]

Am I missing some variable regarding the double & divison?

[Hiroshe]

Don't apologize. Making mistakes is not against any rule, and we've all been there before.

It would be nice to see your new code. Here's a few things to remember though. Remover all of your (int) casts. Also, remember that 1 / 60 = 0 in c++. You might want to try out (1.0 / 60), and see what happens.

[Hiroshe]

Take a look at your math too. It is impossible to convert MPH to minutes and seconds. MPH is distance/time, where as minutes and seconds are just time.

Given a speed and a distance you can calculate time though.

[aegugka]

I tried the following.

int main()
Inline Code Example Here

{


double miles_per_hour, mins, secs, M, Y;
{
    cout << "What is the miles per hour? ";
    cin >> miles_per_hour;
}   
    M = miles_per_hour;
    Y = (1.0 / 60) * M;
    mins = (double)(1 / Y);
    secs = (double)((1 / Y) - M * 60);
{
    cout << "The pace is " << mins << "minutes" << "and" << secs << "seconds";
}
return 0;

}

The output looks weird. I'm still missing/not thinking on the formula?

[aegugka]

I'm new to C++ and taking a course online which I'm regretting now. I should be taking it in-class.

I'm working on the following.

Many treadmills output the speed of the treadmill in miles per hour (mph) on the console, but most runners think of speed in terms of a pace. A common pace is the number of minutes and seconds per mile instead of mph. Write a program that starts with a quantity in mph and converts the quantity into minutes and seconds per mile. As an example. The proper output for an input of 6.5 mph should be 9 minutes and 13.8 seconds per mile.

I hope this makes sense.

I'm using the math based on what I know and verified on a calculator, but what I am interpreting incorrectly in code?

[Hiroshe]

Oh yeah. Another thing is that you have extra { } at lines 11, 14, 19 nd 21. It's not causing your crash, but it's not needed.

The output looks weird possibly because your cout is formatted weirdly. Try:

 cout << "The pace is " << mins << " minutes and " << secs << " seconds." << endl;

instead. Yes, your physics is flawed, as I have mentioned above.

[aegugka]

If the MPH = 6.5, then I divide 60/6.5 that gives me 9.230769230769231.

I need to drop the decimals so I have 9 minutes.

Then for the secodns I need to subtract the minutes value (9.0 from 9.230769230769231) that gives me .230769230769231 that I multiply by 60 which gives me 13.84615384615385 that I round up to 13.8 seconds.

What can I do in the formula to achieve that output?

[Hiroshe]

Ok, so the program determines how long it would take to travel 1 mile given MPH.

You have already figured out double minutes = 60 / mph; in your last post, assuming mph is a double. Good start.

One way to drop the decimal is to convert it back to an integer! For example, try cout << (int)(6.5) << endl; and see what comes out.

Your also right for calculating the seconds. I think you can work out the formula for yourself though.