Hi I dont want the extra bracket inside the list thats been outputted so how would I fix that?
This is the code:
def my_code(list1, list2, index):
index = ['a','b','c']
list2 = [2]
list1 = [1,2,3]
list1.insert(2,index)
return list1
and it returns:
[1, 2, ['a', 'b', 'c'], 3]
I dont want the brackets from inside!
Use slice and extend(), for example:
mylist1 = [1,2,3]
mylist2 = ['a','b','c']
# slice mylist into two temporary lists at index 2
t1 = mylist1[0:2]
t2 = mylist1[2:]
# now use list extend()
t1.extend(mylist2)
t1.extend(t2)
print(t1) # [1, 2, 'a', 'b', 'c', 3]
Another option, insert one element at a time. Do it in reverse order if you want to keep the insert position constant ...
mylist1 = [1,2,3]
mylist2 = ['a','b','c']
for e in reversed(mylist2):
# insert each element e at index 2 of mylist1
mylist1.insert(2, e)
print(mylist1) # [1, 2, 'a', 'b', 'c', 3]
With enumerate().
>>> mylist1 = [1,2,3]
>>> mylist2 = ['a','b','c']
>>> for index, item in enumerate(mylist2, 2):
... mylist1.insert(index, item)
...
>>> mylist1
[1, 2, 'a', 'b', 'c', 3]
Flatten list approach.
def flatten(container):
for i in container:
if isinstance(i, list):
for j in flatten(i):
yield j
else:
yield i
def my_code(list1, list2, index, flatten):
list1.insert(2,index)
return list(flatten(list1))
if __name__ == '__main__':
list1 = [1, 2, 3]
list2 = [2]
index = ['a','b','c']
print my_code(list1, list2, index, flatten)
#--> [1, 2, 'a', 'b', 'c', 3]
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