Hi all, I have a question on how to reverse an integer array recursively with only 2 paramters.
#include <stdio.h>
void reverseAr(int ar[], int size);
int main()
{
int size; //Array size
int ar[100]; //The array itself
int i; //Index to be read in the array
int numbers; //User input digits
printf("Enter size: ");
scanf("%d",&size);
printf("Enter %d numbers: ", size);
for (i = 0; i < size; i++)
{
scanf("%d",&numbers);
ar[i] = numbers;
}
void reverseAr(int ar[], int size)
return 0;
}
void reverseAr(int ar[], int size)
{
int temp;
int start;
int end;
int n;
//How could I do a reverse of array recursively?
}
/*
I have thought of the possibility:
Imagine I have an array of 4, with the input as 1 2 3 4 respectively.
Midpoint refers to half of the 'size' position.
start & end refers to the position to be swapped.
start & end is always 1 position smaller than midpoint & size respectively (Index start from 0).
1 2 3 4 -> size = 4, midpoint = 2.
end = 3, start = 1
1 4 3 2 -> size = 3, midpoint = 1
end = 2, start = 0
3 4 1 2 -> size = 2, midpoint = 1
end = 1, start = 0
4 3 2 1 -> Done!!
Example 2: I have array size of 3, with input as 1 2 3
1 2 3 -> size 3, midpoint = 1
end = 2, start = 0
3 2 1 -> Done
Example 3: I have array size of 5, with input as 1 2 3 4 5
1 2 3 4 5 -> size 5, midpoint = 2
end = 4, start = 1
1 5 3 4 2 -> size 4, midpoint = 2
end = 3, start = 1
1 4 3 5 2-> size 3, midpoint = 1
end = 2, start = 0
3 4 1 5 2 -> size 2, midpoint = 1
end = 1, start = 0
4 3 1 5 2 -> size 1, midpoint = 0
end = 0, start = 0
I could not get what I need >.< Any help?
*/