Python implementations of markdown parsers that can produce HTML

[Irene26]

Can somebody help me to convert markdown to html using python language.
I'm not a programmer but i want to understand some basic things in programming, and now i'm trying to make this conversion.

Can somebody show me for example how to convert this:
https://gist.githubusercontent.com/Irene26/6da8be01b46f07bf2a48/raw/6ef8e49a7c50e0aa1ae7465f6069f0a262b0ad84/gistfile1.txt

to look like this:

https://gist.githubusercontent.com/Irene26/a05c52826fcd680cbd74/raw/22a44879753b137e28d25affefa21912dfdb6912/gistfile1.txt

I'll be very thankfull if somebody will help me to understand this thing.

I was trying to do something like this. But i think it's not a good idea.

import os
import sys
import fileinput


searchquery = '#'
searchquery2 = '##'
searchquery3 = '######'
prefix = '<h1>'
suffix = '</h1>'
prefix2 = '<h2>'
suffix2 = '</h2>'
prefix3 = '<h6>'
suffix3 = '</h6>'
paragraph1 = '<p>'
paragraph2 = '</p>'

with open('file.txt') as f1:
    with open('file2.txt', 'a') as f2:
        lines = f1.readlines()
        for i, line in enumerate(lines):
            if i == 0:

                if line.startswith(searchquery3):
                    line.replace("######", "")
                    f2.write('%s%s%s' % (prefix3, line[7:].rstrip('\n'), suffix3))
                elif line.startswith(searchquery2):
                    line.replace("##", "")
                    f2.write('%s%s%s' % (prefix2, line[3:].rstrip('\n'), suffix2))
                elif line.startswith(searchquery):
                    line.replace("#", "")
                    f2.write('%s%s%s' % (prefix, line[2:].rstrip('\n'), suffix))

            if i > 0:

                if line.startswith(searchquery3):
                    line.replace("######", "")
                    f2.write('\n\n%s%s%s' % (prefix3, line[7:].rstrip('\n'), suffix3))
                elif line.startswith(searchquery2):
                    line.replace("##", "")
                    f2.write('\n\n%s%s%s' % (prefix2, line[3:].rstrip('\n'), suffix2))
                elif line.startswith(searchquery):
                    line.replace("#", "")
                    f2.write('\n\n%s%s%s\n' % (prefix, line[2:].rstrip('\n'), suffix))

            if not line.startswith('#') and line not in ['\n', '\r\n']:
                f2.write('\n\n%s%s%s' % (paragraph1, line.rstrip('\n'), paragraph2))

[Gribouillis]

Hm, you want to understand some basic things in programming, but the task of converting markdown to html is not such a basic thing. I would recommend it only to experienced programmers.

Such modules already exist: you can install the markdown module, then use its conversion function described here

import codecs
import markdown
input_file = codecs.open("some_file.txt", mode="r", encoding="utf-8")
text = input_file.read()
html = markdown.markdown(text)

You could perhaps look in the source code of the markdown module to see how hard it is.

[snippsat]

There is also a markdown2 module.

import markdown2

markdown = """\
# Hello, how are you
I'm fine, thank you

I know that it is not so **hard**
but for me it's not so *easy*

What is ##this?

How about `*this*`?

**it *wor`k`s!***

Let me put a bold link: [**stuff**](http://41.media.tumblr.com/49a58542fd70b8ca39b5bd0d9c9c53aa/tumblr_nob40mvTN41tb9nzio1_500.jpg)
## Okay, part two

But there's no part two!

###### So long!"""

print(markdown2.markdown(markdown))

"""Output-->
<h1>Hello, how are you</h1>

<p>I'm fine, thank you</p>

<p>I know that it is not so <strong>hard</strong>
but for me it's not so <em>easy</em></p>

<p>What is ##this?</p>

<p>How about <code>*this*</code>?</p>

<p><strong>it <em>wor<code>k</code>s!</em></strong></p>

<p>Let me put a bold link: <a href="http://41.media.tumblr.com/49a58542fd70b8ca39b5bd0d9c9c53aa/tumblr_nob40mvTN41tb9nzio1_500.jpg"><strong>stuff</strong></a></p>

<h2>Okay, part two</h2>

<p>But there's no part two!</p>

<h6>So long!</h6>
"""

[Gribouillis]

In order to see the source code, install the markdown or markdown2 module first, then visit the folder named markdown or markdown2. You can type in python

>>> import markdown
>>> print(markdown)

This should give you the path to the folder. All the python files in this folder are part of the module's source code.