# Welcome To Smart Calculator with AI v1.0.
# Please try this code on PC COMMAND PROMPT OR 'PyCharm' for Better Experience (Recommended).
# Please Leave Comment if anything is wrong in this code OR You have any implementation idea.
# Like if You Enjoy the code : By KEYUR SURELIYA.
# 're' : Use to check whether the string contains the specific characters or not.
# Default Return Value : True
import re
class AdvancedCalc:
# Defining Variables.
__x = "" # This is self.__x Number User Enters.
__y = "" # This is self.__y Number User Enters.
__equation = 0 # This will get entire equation.
__result = 0 # Result will store here.
# This is initialization Function.
def __init__(self):
print("\n....Welcome to Advanced Calculator v2.0.....\n")
print('Equation Examples (Possibilities) :-')
print(' -> With Space :-')
print(' 1. \'1 + 1\'')
print(' 2. \'-1 + -1 \'')
print(' 3. \'1.1 + 1.1 \'')
print(' 4. \'-1.1 + -1.1 \'')
print(' -> Without Space :-')
print(' 1. \'1+1 \'')
print(' 2. \'-1+-1 \'')
print(' 3. \'1.1+1.1 \'')
print(' 4. \'-1.1+-1.1 \'')
print(' -> One Sided Space :-')
print(' 1. \'1 +1 \'')
print(' 2. \'1+ 1 \'')
print(' 3. \'-1 +-1 \'')
print(' 4. \'-1+ -1 \'')
print(' 5. \'1.1 + 1.1 \'')
print(' 6. \'1.1+ 1.1 \'')
print(' 7. \'-1.1 +-1.1 \'')
print(' 8. \'-1.1+ -1.1 \'')
print('Type \'Exit\' to Exit from Program.')
# This function will get
# Fetching OR Get Input from User.
def fetchvalues(self, val):
self.__equation = input("\nEnter The Equation Here : ")
if not self.__equation == "exit" or self.__equation == "Exit" or self.__equation == "EXIT":
# This Conditions & Regular Expression is Exist Only Here.
while not re.fullmatch('([\-]?\d+[\.]?\d+)(\s?)(\+)?(\-)?(\*)?(\/)?(\s?)([\-]?\d+[\.]?\d+)',
self.__equation):
if self.__equation == "exit" or self.__equation == "Exit" or self.__equation == "EXIT":
print("\nThank You For Visiting...!")
exit()
else:
self.__equation = input("Please Enter Valid Equation Here : ")
else:
# This will exit the program.
print("\nThank You For Visiting...!")
exit()
# Calculate the Values as User needs.
def calculate_the_values(self):
# Get The Equation from User.
self.fetchvalues(0)
# Calculate Values Here
# Get The First Number out of Equation.
self.__x = re.findall('([\-]?\d+[\.]?\d+)(?:\s?)(?:\+)?(?:\-)?(?:\*)?(?:\/)?(?:\s?)(?:[\-]?\d+[\.]?\d+)',self.__equation)
# Get The Second Number out of Equation.
self.__y = re.findall('(?:[\-]?\d+[\.]?\d+)(?:\s)?(?:\+)?(?:\-)?(?:\*)?(?:\/)?(?:\s)?([\+\-]?\d+[\.]?\d+)',self.__equation)
# Get the Operator out of Equation.
operator = re.findall('(?:[\-]?\d+[\.]?\d+)(?:\s)?(\+)?(\-)?(\*)?(\/)?(?:\s)?(?:[\-]?\d+[\.]?\d+)',self.__equation)
# Find The Operator And Do The Math.
for x in operator[len(operator) - 1]:
if x == "+":
self.__result = float(self.__x[0]) + float(self.__y[0])
break
elif x == "-":
self.__result = float(self.__x[0]) + float(self.__y[0])
break
elif x == "*":
self.__result = float(self.__x[0]) * float(self.__y[0])
break
elif x == "/":
self.__result = float(self.__x[0]) / float(self.__y[0])
break
# Return The Result Value.
return self.__result
# Now we call the function here to see this working.
Answer = AdvancedCalc().calculate_the_values().__float__()
print("\nAnswer is : %0.2f" % Answer)
# This will ask user if he/she want to run this again.
choise = input('\nDo you want to Start Again? (Y/N) : ')
# This is to make sure that user inputs only 'Y'/'y'/'n'/N' keys.
while not re.search("[Y][y][n][N]", choise):
# If user says yes then we will run this.
if choise == "y" or choise == "Y":
# NOTE : This Loop will continue Until you Select Exit Option.
Answer = AdvancedCalc().calculate_the_values().__float__()
print("\nAnswer is : %0.2f" % Answer)
choise = input('\nDo you want to Start Again? (Y/N) : ')
# If User says No then we will say goodbye.
else:
print('\nThank You For Visiting...!')
break
# Complete v1.0.
Keyur_2 0 Newbie Poster
ddanbe 2,724 Professional Procrastinator Featured Poster
rproffitt commented: Maybe this was written by an AI (machine.) +11
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