Need quikfix

[Mix]

Ok I have a program that accepts input from a file. it reads in inputs and is supposed to close automagically when it sees the number '42'. Only problem, I can read the input just dont know how to look for 42.

Here's the code? HELP plz.

import java.io.* ;
 public class life42 {
 public static void main (String args[]) {
 if (args.length == 1 )
 {
  try 
  {
  FileInputStream fstream = new
   FileInputStream(args[0]) ;
 DataInputStream in =
 new DataInputStream (fstream);
 
 while (in.available() !=0)
  System.out.println(in.readLine()) ;
 
}
in.close();
}
catch (Exception e)
{
 System.err.println("There was an error reading your input");
}
System.out.println("Input read");
}}}

[Dukane]

Can you also give us a sample of the file?

I would use a Scanner object to read each token in the file. Then if that token matches 42, exit.

[Mix]

Something says try that Scanner and see what happens. Looking into it right now, looks like exactly what I needed

[zorr]

cheak this

import java.io.* ;
import java.util.*;
 public class life42 {
 public static void main (String args[]) {
 try 
  {
  FileInputStream fstream = new FileInputStream("ex.txt") ;
 DataInputStream in =new DataInputStream (fstream);
 
 while (in.available() !=0)
      {
     
     String str=new String(in.readLine());
     char[] c=str.toCharArray();
     
    
    for ( int i = 0; i  < c.length; i++ ) 
          {
        if(c[i]=='4')
              {
            if(c[i+1]=='2')
            break;
            }

       System.out.print ( c [ i ]  ) ; 
          }       
           }
 in.close();
}
catch (Exception e)
{
 System.err.println("There was an error reading your input");
}
System.out.println("Input read");
}}