I have a program evaluating a straight hand in poker: Here is my code:
int numInRank[14];
cin.get(rankCh);
switch (toupper(rankCh))
{
case '-1': exit(0);
case '?': rank = 0; break;
case 'A': rank = 1; break;
case '2': rank = 2; break;
case '3': rank = 3; break;
case '4': rank = 4; break;
case '5': rank = 5; break;
case '6': rank = 6; break;
case '7': rank = 7; break;
case '8': rank = 8; break;
case '9': rank = 9; break;
case 'T': rank = 10; break;
case 'J': rank = 11; break;
case 'Q': rank = 12; break;
case 'K': rank = 13; break;
bool isStraight(int numInRank[]){
int count = 0;
for(int i = 1; i < 14; i++){
if(numInRank[i] != 0){
count++;
if(i == 13 && numInRank[1] != 0) count++;
}else{
count = 0;
}
if(count == 5) return true;
}
return false;
}
I would like to modify the above code to handle A high and A low straights- I sized my array to 14 instead of 13 to hold both...
Any suggestions...