I have a starting base and I had the idea of using an array name similar to the checkboxes where you would use checkbox[] and let it repeat through a for loop, in this case file[]. But when I go to access it via $_FILES'] it errors. I think there is something wrong with my logic as it is looking wrong but I feel it should work
Any Ideas?
Thanks, Regards X
Can you show us your script ? What is the error that you are getting ?
Thanks Nav33n to the PHP rescue ;)
Theres way too much code to copy n paste so I will try break it up best I can, code:
switch($_POST['submit']) {
case 'UPLOAD':
now a whole bunch of code access variables and databases then
$file = $_FILES['file']['name'];
again a whole bunch of code
}
<input type="file" id="file" name="file">
<input type="submit" id="submit" name="submit" value="UPLOAD">Thats the nuts of my code im trying to get working. (This works)
But im trying to make the type="file" an array id/name so its like id="file[]" name="file[]".
Then call it again at $_FILES']; using a for loop using 'index'.
Anyways no luck ill try again in the morning, any ideas?
Thanks Again, Regards X
<?php
if(isset($_POST['submit'])) {
for($i=0;$i<count($_FILES['fileupload']);$i++) {
print $_FILES['fileupload']['name'][$i]."<br />";
}
}
?>
<html>
<body>
<form name="upload" method="post" action="upload.php" enctype="multipart/form-data">
<table>
<tr><td>
<input type="file" name="fileupload[]">
</td></tr>
<tr><td>
<input type="file" name="fileupload[]">
</td></tr>
<tr><td>
<input type="file" name="fileupload[]">
</td></tr>
<tr><td>
<input type="file" name="fileupload[]">
</td></tr>
<tr><td>
<input type="submit" name="submit">
</td></tr>
</table>
</form>
</body>
</html>This works for me! :)
Man I dont know what to say...
Your a PHP Guru,who has come to the rescure and helped me so much time and time again.
Same concept worked on my webpage first time.
Thankyou =)
PS: I was just wondering what is the different between using isset and just $_POST[] because i was reading at php.net and couldnt understand anything but only if you wanted to pass a variable?
:) You are welcome! I am not a guru! There are sooooo many things that I am not aware of.
isset() checks whether a variable is set, has a value (even null) in it. So, this would pass the value of that variable, only if its set.
if(isset[$_POST['name'])){
$name=$_POST['name'];
} else {
echo "Name is not set.";
}As I said, If you assign null to a variable and check if it is set, it would return true.
$x="";
if(isset($x)){
echo "X is set";
} else {
echo "X is not set.";
}In this case, it returns X is set, even though it doesn't have any value.
Cheers,
Naveen
Ahhh ok Thankyou once again, off to read my other thread that you answered =P
Can u please give me whole code for multiple images uploading in php.. i have tried.. but its not working... plz plz help me.. its very urgent.. plz reply as soon as possible.
We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.