Member Avatar for Eko

Hey guys ,

While playing with jquery i've come across the following situation :

$(document).ready(function(){

	$("div")[0].css("background-color","blue");
});

I get an error everytime i try to call any method on a particular element from the wrapper set .

I tried with the get()

$("div").get(0);

Same stuff .

I can't spot what the problem is .

Thank u

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Dani AI

Generated

Nice catch by — and thanks to @redsquare for the assist. A few practical patterns and tips that complement the thread and are useful when working with single elements from a jQuery collection.

Use a jQuery method that returns a jQuery object (no extra wrapping needed):

$("div").eq(0).css("background-color", "blue");

If you already have a plain DOM node (from native APIs or an indexed access), wrap it back to call jQuery methods:

var first = document.querySelector("div");
$(first).css("background-color", "blue");

Work in loops without repeated wrappers by caching jQuery objects:

var $divs = $("div");
var $first = $divs.eq(0);
$first.addClass("first");

Troubleshooting tips

  • If you see "'... is not a function'" check whether the value is a DOM node or a jQuery object. Methods like .css() live on jQuery objects.
  • For bulk DOM-only operations (manipulating properties directly or reading node info), native nodes are slightly faster — but wrap them when you need jQuery helpers.
  • When selecting a single element by position, prefer .eq() for clarity; use native indexing only when you intentionally want a DOM node.

These patterns keep intent explicit (are you working with DOM or jQuery?) and avoid the common error discussed in this thread.

Member Avatar for Eko

I found out what the problem is .

When getting an element from the wrapper set ( by index array notation or by get(index ) ), it returns a javascript element , NOT a jquery object and thus everytime i try to call a method from the jquery library on the extracted javascript element i get an error like ( " method name is not a function " ).

The solution to my problem :

$(document).ready(function(){

$("div:first").css("background-color","blue");

});

I hope this topic will help others that ran over the same problem .

Many thanks to redsquare from the jquery irc channel for all the help .

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