arunajasmine 0 Newbie Poster

HI,
i am new to JQUery and Ajax.I am trying to use the value returned from the Ajax call to the another Ajax call..
like

$.ajax({
         type: "POST",
         url: "http://localhost/FormBuilder/index.php/forms/saveForm/",
               async: false,
                 data: "formname="+formname+"&status="+status,
                 success: function(msg){
                 //alert( "Data Saved: " + msg);                         

                            getformid=msg; 
                            }//success
                 });//ajax 

$("#fb_contentarea_col1down21 div").each(function() { 
//alert("Form id "+getformid);
						var checked="false";	 
							var id=$(this).attr("id");
							
							//var fname=$("#label"+id+"").text();
						
							var fsize=$("#input"+id+"").width();
							
							var ftype=$("#input"+id+"").attr('data-attr');
							
							var finstr=$("#instr"+id+"").text();

                            var fname=$("#label"+id+"").clone().html().replace(/<span.*/,'');

							if($("#label"+id+"> span.req").length > 0)
							{
							 
							 checked="true";
							 
							}
                                                             
       									
							                        $.ajax({
										   type: "POST",  
										   async: false,
										  url: "http://localhost/FormBuilder/index.php/forms/saveField",
                                     						
  data: "sequence_no="+id+"&name="+fname+"&type="+ftype+"&size="+fsize+"&instr="+finstr+"&formid="+getformid+"&required="+checked,

										   success: function(msg){
										//alert( "Data Saved: " + msg);
											}//success
									       });//ajax


The First Ajax call returns the Formid and even alerts it correctly in the Div ,But the returned value in getformid is not reflected in the second ajax call . Please sugggest me

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