$query = "INSERT INTO update_feedback (updateID,comment,timestamp) VALUES ('$updateID','$comment',NOW())";
$result = mysqli_query($dbcon,$result) or die('Error saving feedback into database. ' .mysqli_error($dbcon));
Gives me this error:
Error saving feedback into database. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1