hi all,
i am having a projects page, in which we can create a project by giving projectname and allocate some memory(we had restriction on memory i;e 60MB). so i had created a project and allocated some memory of 65MB. so now i wil get a popup as "insufficient memory" on popup if i press ok that projectname and memory text box also getting empty so i need to get only memory text box empty.
Thank u.
niths -1 Posting Whiz in Training
rajarajan2017
Where is your code?
niths -1 Posting Whiz in Training
Where is your code?
thanks for ur response. here is my code.
<html>
<body>
<script language="javascript" type="text/javascript">
function check()
{
if(document.getElementById('txtname').value == "")
{
alert('Please enter projectname');
return false;
}
if(document.getElementById('createdby').value == "")
{
alert('Please enter createdby');
return false;
}
}
</script>
<form action="projectcreation.php" method="post">
<table align="center">
<tr>
<td style="color: navy;">Projectname</td>
<td><input id="txtname" type="text" name="projectname"></td>
</tr>
<tr>
<td style="color: navy;">Allocated memory</td>
<td><input type="text" name="allocatedmemory"></td>
<td><select name="size">
<option value="MB">MB</option>
<option value="KB" selected="selected">KB</option>
</select>
</td>
</tr>
<?php
if(isset($_POST['btn']))
{
$id=$_GET['f1'];
@session_start();
require_once ("check.php");
createsessions($username,$password,$userid,$projectid,$projectname,$filename,$size,$allocatedmemory,$answer,$usedmemory,$Remainingmemory,$result);
$con=mysql_connect("10.70.1.248","invensis","invensis");
if(!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("database_myproject",$con);
if($_POST[size]== 'MB')
{
$am=$_POST[allocatedmemory] ;
$result=$am*1024;
}
else{
$am=$_POST[allocatedmemory] ;
$result = $am;
}
if($_POST[size]== 'KB')
{
$am=$_POST[allocatedmemory];
$test=round($am/1024,4);
}
else{
$am=$_POST[allocatedmemory];
$test=$am;
}
if( $result < $Remainingmemory)
{
$sql="INSERT INTO projects(projectname,allocatedmemory,createdby)
VALUES ('$_POST[projectname]','$test MB','$_SESSION[username]')";
echo "New Project Added";
if(!mysql_query($sql,$con))
{
die('Error:' . mysql_error());
}
}
else
{
echo "<script language='javascript'>
alert('Insufficient Memory');
</script>";
}
}
?>
<td></td>
<td><input type="submit" name="btn" value="Submit" onclick="return check();"></td>
</table>
</form>
</body>
</html> rajarajan2017
I think your page got refreshed, then you can use the method= "post" or "get" r8?. Retrieve the value by using:
$pname=_POST;
display the value in the project textbox
niths -1 Posting Whiz in Training
I think your page got refreshed, then you can use the method= "post" or "get" r8?. Retrieve the value by using:
$pname=_POST;
display the value in the project textbox
sorry i didnt understand as i am new to php. can u say it in brief.
rajarajan2017
<?php
$pname=_POST['projectname'];
echo $pname;
?>And I am not a programmer in php little bit I know. Trying to help thats it!
niths -1 Posting Whiz in Training
<?php $pname=_POST['projectname']; echo $pname; ?>And I am not a programmer in php little bit I know. Trying to help thats it!
ya thank u i got it.
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