Can't Update UI Sortable Items

[fantasma]

Greetings

I've got this code that tries to update a sortable list (not really a list since I don't use ordered lists, but divs). The thing is, I tested in another area of my site and it's working fine. When moving forward to another list, it just doesn't seem to work at all...

This is the code that is working

<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.6/jquery-ui.js"></script>

<script>
$(document).ready(
function() {
$("#cont_etiquetas").sortable({
	update : function () {
	serial = $('#cont_etiquetas').sortable('serialize');
	$.ajax({
	url: "../includes/updateList.php?mod=noticias",
	type: "post",
	data: serial,
	error: function(){
	alert("theres an error with AJAX");
}
});
}
});
}
);

This is a working example of my HTML/PHP code

<div id="cont_etiquetas">

		<?php 
		
		
		$sentence = "SELECT * FROM $table ORDER BY sort ";
		$query = mysql_query($sentence);
		if(!$query)
		{
			echo "Erro ao executar a query".mysql_error();
		}
		while ($row = mysql_fetch_array($query)){
		
		$titulo=$row['titulo_noticia'];
		$id=$row['ID'];
		$descricao = $row['corpo_noticia'];
		$data_adic = $row['data'];
		
		
		echo'<div class="etiquetas" id="menu_'.$id.'">';
		
		
				echo '<div class="tit_etiq">';
					echo $titulo;
				echo'</div>';
		
		echo'<div class="botoes_comando">
					
					<a href="#"><div class="visualiza" id="visualiza"></div></a>
					<a href="#" onClick="show3()"><div class="edita"></div></a>
					<a href="../crud/delete.php?id='.$id.'&mod='.$table.'" onclick="return show_confirm()"><div class="elimina" id="delete"></div></a>
					<a href="#" onClick="show()"><div class="upimagem"></div></a>
				</div>';
				
				
			echo '</div>';

And here are the non-working examples

jQuery

<script>
$(document).ready(
function() {
$("#container_submenu").sortable({
	update : function () {
	serial = $('#container_submenu').sortable('serialize');
	$.ajax({
	url: "../includes/updateList.php",
	type: "post",
	data: serial,
	error: function(){
	alert("theres an error with AJAX");
}
});
}
});
});
</script>

$sentence = "SELECT menu.ID, menu.titulo, menu.id_modulo FROM menu, modulos WHERE menu.id_modulo = modulos.id_modulo AND modulos.nome_mod='Servicos' ORDER BY sort";

		
		$query = mysql_query($sentence);
		if(!$query)
		{
			echo "Erro ao executar a query".mysql_error();
		}
		echo '<div id ="container_submenu">';
		while ($row = mysql_fetch_array($query)){
		
		$id_sub = $row['ID'];
		$titulo_menu = $row['titulo'];
		
			
		if(isset($_GET['id_menu']))
		{
			if($_GET['id_menu']==$id_sub)
			{
				echo '<div class="etiquetas_subm_active" id="menu_'.$id_sub.'">';
			}
			else
			{
				echo'<div class="etiquetas_subm" id="menu_'.$id_sub.'">';
			}
		}
		else echo'<div class="etiquetas_subm" id="menu_'.$id_sub.'">';
		echo '<div class="tit_etiq_subm">';
				
				echo '<a href="back_servicos.php?id_menu='.$id_sub.'">';
				echo '<div class="subm_records">';
				echo $titulo_menu;
				echo '</div>';
				echo '</a>';
				echo '<br>';

		echo'</div>';
		echo'<div class="botoes_comando_subm">
			
			<a href="view.php?id='.$id_sub.'"><div class="edita"></div></a>
			<a href="../crud/delete.php?id='.$id_sub.'&mod=menu" onclick="return show_confirm()"><div class="elimina" id="delete"></div></a>
			<a href="../upload/upload_crop.php?id='.$id_sub.'&mod=menu"><div class="up_imagem"></div></a>
		</div>';
		echo'</div>';
		
		}
	
		
	
	
	echo'</div></div>';

Thanks in advance for any possible help

[fantasma]

Anyone can help me please? I really needed this working