Hello everyone,
I'm trying to write a script which accepts URL by GET and then validates the URL before processing it.
for the sake of arguement lets say that the URL I'm expecting is in this format
http://mysite.com/myscript.php?url=http://blahblah.blahblah.bla/blahblah/blahblah/blahblah.bla
http://subdomain.domain.tld/section/category/file.ext
I need to validate the part which is a link to a XML; i.e, my URL might be like these
http://gradefive.belmontprimary.edu/grades/science/peter.xml
https://gradesix.belmontprimary.edu/grades/maths/geometry/lisa.xml
http://gradeeight.belmontprimary.edu/grades/maths/calculus/sandra.xml
I don't know wether if the XML files would be on a secure server (https) or unsecure one (non-https) at the moment, and also I don't know what the contents of the files may be. All I know for sure is that these are the XML files which I need to use for my project.
so far, I have snooped around and found this code
function isValidURL($link)
{
$urlregex = '^(https?|s?ftp\:\/\/)|(mailto\:)';
$urlregex .= "[a-z0-9+$_-]+(.[a-z0-9+$_-]+)+";
$urlregex .= '(\?[a-z\+&\$_\.\-][a-z0-9\;\:@\/&%=\+\$_\.\-]*)?';
if(preg_match('/'.$urlregex.'/i', $link))
{
return true;
}
else
{
return false;
}
}
function getXMLData($url){
if(!isValidURL($url)) {
echo "Please enter valid URL including http://<br>";
}
else{
try{
$savedXML = file_get_contents($url);
echo "thanks";
return $savedXML;
}catch(Exception $e){
die($e.getMessage());
}
}
}
but this is not what I exactly need. can anyone please help me by solving this issue?
thanks in advance.