Member Avatar for DaveyMoyes

Hi everyone, I have a script running on my page that uploads a new image.
I am getting the information from the mysql ok, by using

if (isset($_POST['var'])) {

Once the vailidation is complete, at the moment I am using

header("Location: url.php");

to reload the page to display the new photo uploaded.
How do I include the above post var in the header Location url.php
Is it possible with open and close php tags

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  • Latest Post Latest Post by dschuett

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Brief, practical guidance and safer alternatives (adds to 's reply)

is correct that sending a redirect after the upload will refresh the view and can carry data to the next page via the URL. A few important caveats and better-practice options that address common problems seen with this pattern:

  • Redirects must be sent before any output is emitted; otherwise PHP will report "headers already sent." Use headers_sent() to detect this and avoid closing PHP/printing HTML before the redirect. (See PHP: headers_sent().)
  • Never expose sensitive data in the query string. For short, non-sensitive values an encoded query parameter works, but larger or private values should be passed as a database record id or via the session. filter_input() helps sanitize incoming values. (See PHP: filter_input().)
  • URL-encode any value placed into a query string to avoid broken URLs. Consider rawurlencode() when building the redirect target. (See PHP: rawurlencode().)
  • Use the Post/Redirect/Get pattern so form resubmission is avoided; issuing a 303 status after POST makes the browser fetch the next page with GET. (See HTTP 303 See Other.)
  • Always stop script execution after sending the Location header to prevent accidental output or logic running after the redirect.

Common troubleshooting: check for UTF-8 BOM or stray whitespace before the first <?php, inspect response headers in browser dev tools, and log headers_sent() output. For an image upload workflow, the most robust approach is: save the file and record, redirect with only the record id (or set a session flag), then let the display page look up and show the saved image. (See PHP: header() for details on redirects.)

Member Avatar for dschuett

Set your $_POST['var'] as a variable:

$var = $_POST['var'];

Then you can pass the variable through your url using:

header("Location: url.php?var=$var");

In url.php you can use the variable however you need by doing the following:

$passed_var = $_GET['var'];
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