Member Avatar for reemasmartin 
hai everyone..i have run this file in my server.the following error is display

Notice: Undefined index: name in F:\wamp\www\examples1\register.php on line 8

Notice: Undefined index: username in F:\wamp\www\examples1\register.php on line 9

Notice: Undefined index: emailid in F:\wamp\www\examples1\register.php on line 10

Notice: Undefined index: password in F:\wamp\www\examples1\register.php on line 11

Notice: Undefined index: cpassword in F:\wamp\www\examples1\register.php on line 12
Anyone help me..

<?php
$host ='localhost';
$user ='root';
$password ='';
$database ='dta';
$conn = mysql_connect($host,$user,$password)or die ('server is not connect');
mysql_select_db($database,$conn);
$name = mysql_real_escape_string($_POST['name']);
$username = mysql_real_escape_string($_POST['username']);
$emailid = mysql_real_escape_string($_POST['emailid']);
$password = mysql_real_escape_string($_POST['password']);
$cpassword = mysql_real_escape_string($_POST['cpassword']);
if(isset($_POST['submit']))
{
$query = " insert into users(name,username,emaiid,password,)values ('$name','$username','$emailid','$password')";
$res = mysql_query($query);
header('location:register_success.php');
exit();
}
?>
<html>
<head>
<title> registeration form</title>
</head>
<body>
<form>
<form id= "register form" name="register form" method="post" action="">
  <table width="300" border="0" align="center" cellpadding="2" cellspacing="0">
  <tr>
      <th> name </th>
      <td><input name="name" type="text" class="textfield" id="name" /></td>
    </tr>
    <tr>
      <th>user name </th>
      <td><input name="username" type="text" class="textfield" id="user name" /></td>
    </tr>
    <tr>
      <th width="124">email id</th>
      <td width="168"><input name="emailid" type="text" class="textfield" id="email id" /></td>
    </tr>
    <tr>
      <th>Password</th>
      <td><input name="password" type="password" class="textfield" id="password" /></td>
    </tr>
    <tr>
      <th>Confirm Password </th>
      <td><input name="cpassword" type="password" class="textfield" id="cpassword" /></td>
    </tr>
    <tr>
      <td> </td>
      <td><input type="submit" name="submit" value="Create account" /></td>
    </tr>
  </table>
</form>
</body>
</html>
Edited by reemasmartin because: scrip
  • 2 Contributors
  • 8 Replies
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  • 1 Hour Discussion Span
  • Latest Post Latest Post by reemasmartin
Member Avatar for pritaeas

A $_POST variable may not have a value, so you should do the following:

$name = isset($_POST['name']) ? mysql_real_escape_string($_POST['name']) : '';

or move the assignments within the if.

Add on: Your query is incorrect, check that you have the syntax right.

Edited by pritaeas
Member Avatar for reemasmartin

hai.thanks.nw script is working.but i am new beginner for php developer.y used for this ?something :'';
pls tell me

Member Avatar for reemasmartin

hai.thanks.nw script is working.but i am new beginner for php developer.y used for this ?something :' ';
pls tell me

Member Avatar for pritaeas

It's called the ternary operator, a shorthand if/else construct. See the manual, example #2.

Member Avatar for reemasmartin

suppose i fill the form and click the submit button.the pages not go to next page.but i includer the header funtion.header('location:register_success.php');

Member Avatar for pritaeas

Did you fix your query, as I mentioned earlier ?

Member Avatar for reemasmartin

$query = " insert into users(name,username,emailid,password,)values ('$name','$username','$emailid','$password')";
i think query is correct

Member Avatar for reemasmartin

my table name is users. my table is create table users(id int(11) auto increment,name varchar(100),username varchar(100),email id varchar (100), password varchar(100), primary key(id));

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