I'm attempting to wrap an auto-generated link around a thumbnail displayed from a Mysql database. Can someone help me with the syntax?
echo "<a href= 'http://www.website/link.php?field=".urlencode(img src='".$showimage"' height='10px' width='50px' />) . "'>$showimage</a>";
Thanks!
I can't make head nor tail of that. It looks mashed to me. Usually:
<a href="..." ><img src="..." /></a>
Where ... will be urls. SO the $showimage I don't get. Is it an url or full image tag code or what?
I'm assuming here that the content of the link is an image not text/filename.
I have dynamically created links that attach themselves to information pulled from the database.
echo "<a href= 'http://www.website.com/test/link.php?field=".urlencode($imgrow['data'] ) . "'><h3>$imgrow[data]</h3></a>";
The above works. I wanted to do the same for the following thumbnails:
echo "<img src='".$showimage."' height='203px' width='135px' />";
What is the code to create an auto-generated link around that image?
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