<?
$connection = mysql_pconnect("***","***","***");
mysql_select_db("***");
$id = mysql_real_escape_string(strip_tags(stripslashes($_GET['id'])));
$getUser = mysql_query("SELECT * FROM user WHERE id='".$id."'");
$gU = mysql_fetch_object($getUser);
$Background = $gU->Background;
if (empty($Background)) {
$Background = "";
}
$Hat = $gU->Hat;
if (empty($Hat)) {
$Hat = "";
}
class StackImage
{
private $image;
private $width;
private $height;
public function __construct($Path)
{
if(!isset($Path) || !file_exists($Path))
return;
$this->image = imagecreatefrompng($Path);
imagesavealpha($this->image, true);
imagealphablending($this->image, true);
$this->width = imagesx($this->image);
$this->height = imagesy($this->image);
}
public function AddLayer($Path)
{
if(!isset($Path) || !file_exists($Path))
return;
$new = imagecreatefrompng($Path);
imagesavealpha($new, true);
imagealphablending($new, true);
imagecopy($this->image, $new, 0, 0, 0, 0, imagesx($new), imagesy($new));
}
public function Output($type = "image/png")
{
header("Content-Type: {$type}");
imagepng($this->image);
imagedestroy($this->image);
}
public function GetWidth()
{
return $this->width;
}
public function GetHeight()
{
return $this->height;
}
}
$Image = new StackImage("".$Background."");
$Image->AddLayer("".$Hat."");
$Image->Output();
?>
I get these errors...
PHP Warning: imagepng() expects parameter 1 to be resource, null given in G:\PleskVhosts\social-idiots.com\httpdocs\avi.php on line 57
PHP Warning: imagedestroy() expects parameter 1 to be resource, null given in G:\PleskVhosts\social-idiots.com\httpdocs\avi.php on line 58
This is an old code I have been using for a while, so I have never really worked with images in php...