The user is asked to input a number in either Hex, Octal or Decimal, which is then converted to Hex, Octal & Decimal.
The user can exit the program from the MAIN MENU or by the Escape key after each convertion.
Compiler : Borland Turbo C++ v4.5.
Convert Hex to dec or Octal
Ancient Dragon commented: Nice program, too bad you used such an old obsolete compiler. +24
//****************************************************************************//
// //
// Program Name : ConvDec.cpp //
// //
// Programmer : K.Angel //
// : Novice C++ //
// //
// Description : The user is asked to input a number in either Hex, Octal or //
// Decimal, which is then converted to Hex, Octal & Decimal. //
// The user can exit the program from the MAIN MENU or by //
// the Escape key after each convertion. //
// //
// Compiler : Borland Turbo C++ v4.5. //
// Date : 16/03/2006 //
// //
//****************************************************************************//
#include <iostream.h>
#include <conio.h> // for clrscr() & getche() functions...
#include <stdlib.h> // for exit() function...
const int ESC = 27; // Used for escape sequince
int main()
{
int key = 0;
int choise = 0;
long number;
while(key != ESC)
{
cout << "Choose Your Number Base\n";
cout << "\n\t1. Hexadecimal.";
cout << "\n\t2. Octal.";
cout << "\n\t3. Decimal.";
cout << "\n\t4. Exit.\n\t ";
cin >> choise;
switch(choise)
{
case 1: clrscr();
cout << "Enter a Hex number: ";
cin >> hex >> number;
cout << "\n value in octal = "
<< oct << number << endl;
cout << " value in decimal = "
<< dec << number << endl;
break;
case 2: clrscr();
cout << "Enter a Octal number: ";
cin >> oct >> number;
cout << "\n value in hex = "
<< hex << number << endl;
cout << " value in decimal = "
<< dec << number << endl;
break;
case 3: clrscr();
cout << "Enter a dec number: ";
cin >> dec >> number;
cout << "\n value in octal = "
<< oct << number << endl;
cout << " value in hex = "
<< hex << number << endl;
break;
case 4: clrscr();
cout << "Program terminated by user...";
exit(0);
break; //Unreachable code....
default : clrscr();
cout << "ERROR ~ Invalid selection\n\n";
break;
}
cout << "Press any key to continue or 'Esc' to exit";
key = getche();
clrscr();
}
cout << "Program terminated by user...";
return 0;
}
herge 0 Newbie Poster
Move Clrscr() to between cin and switch and drop all the other clrscr() at case 1: thru case 4: and default:.
You are always Clrscr() anyway so why use the case at all for this?
This also saves some typing?
desai22982 0 Newbie Poster
8000fe80 why this code is not working for this hexa decimal address
guntime 0 Newbie Poster
who the bullshit can write code like that.
Ancient Dragon 5,243 Achieved Level 70 Team Colleague Featured Poster
>>8000fe80 why this code is not working for this hexa decimal address
Data overflow.
On line 73 add cin.clear() to clear out the errors.
Naveed Marwat 0 Newbie Poster
not working properly
messr135 0 Newbie Poster
here's d code i tried....it worked for all conversions
//final conversion-only for decimal input
#include<iostream.h>
#include<conio.h>
#include<string.h>
#include<math.h>
#include<process.h>
main()
{
//too long....the hex case ruins it all and too many switch cases
char a[30],ch;
int len,i,j,pos,whole=0,k=0,n=0,r[30],lenr=0,lenq=0,q[30],h=0,base,base1;
float frac=0;
cout<<"Enter number ";
gets(a);
cout<<"\nEnter choice-\n1. Decimal (d/D)\n2. Octal (o/O)\n3. Hexadecimal (h/H)\n4. Binary (b/B) ";
cin>>ch;
len=strlen(a);
switch(a[0])//for converting the no. inputted into frac and whole part
{
case 'O':
case 'o':base1=8;break;
case 'B':
case 'b':base1=2;break;
case 'H':
case 'h':base1=16;break;
case 'd':
case 'D':base1=10;break;
}
switch(ch)//for final conversion according to choice inputted
{
case 'O':
case 'o':base=8;break;
case 'B':
case 'b':base=2;break;
case 'H':
case 'h':base=16;break;
}
for(i=0;i<len;i++)//code for separating the fractional and whole part
{
if(a[i]=='.')
pos=i;
}
for(i=pos-1,j=0;i>=1,j<pos-1;i--,j++)
{
if(a[0]=='h'||a[0]=='H')
{
switch(a[i])
{
case 'A':whole+=10*(pow(base1,j));break;
case 'B':whole+=11*(pow(base1,j));break;
case 'C':whole+=12*(pow(base1,j));break;
case 'D':whole+=13*(pow(base1,j));break;
case 'E':whole+=14*(pow(base1,j));break;
case 'F':whole+=15*(pow(base1,j));break;
default:whole+=a[i]*(pow(base1,j));
}
}
else
{
a[i]=a[i]-48;
whole+=a[i]*(pow(base1,j));
}
}
for(i=pos+1,j=1;i<len,j<=len-pos-1;i++,j++)
{
if(a[0]=='h'||a[0]=='H')
{
switch(a[i])
{
case 'A':frac+=10*(pow(base1,-j));break;
case 'B':frac+=11*(pow(base1,-j));break;
case 'C':frac+=12*(pow(base1,-j));break;
case 'D':frac+=13*(pow(base1,-j));break;
case 'E':frac+=14*(pow(base1,-j));break;
case 'F':frac+=15*(pow(base1,-j));break;
default:frac+=a[i]*(pow(base1,-j));
}
}
else
{
a[i]=a[i]-48;
frac+=a[i]*(pow(base1,-j));
}
}
if(ch=='d'||ch=='D')
{
cout<<"\nConverted Decimal no. is "<<frac+whole;
getch();
exit(0);
}
else
{
while(whole>=base)//coverting whole part
{
r[n]=whole%base;
whole=whole/base;
n++;
lenr++;
}
while(h<4)//coverting fractional part
{
frac=frac*base;
q[h]=frac/1;
frac=frac-q[h];
h++;
lenq++;
}
cout<<"\nCoverted no.is ";
cout<<whole;
for(n=lenr-1;n>=0;n--)
{
if(ch=='h'||ch=='H')
{
switch(r[n])
{
case 10:cout<<"A";break;
case 11:cout<<"B";break;
case 12:cout<<"C";break;
case 13:cout<<"D";break;
case 14:cout<<"E";break;
case 15:cout<<"F";break;
default:cout<<r[n];
}
}
else
cout<<r[n];
}
cout<<".";
for(h=0;h<lenq;h++)
{
if(ch=='h'||ch=='H')
{
switch(r[n])
{
case 10:cout<<"A";break;
case 11:cout<<"B";break;
case 12:cout<<"C";break;
case 13:cout<<"D";break;
case 14:cout<<"E";break;
case 15:cout<<"F";break;
default:cout<<r[n];
}
}
else
cout<<r[n];
}
}
getch();
} karley 0 Newbie Poster
How can i convert hexadecimal to binary? Or kindly give me a c++ codes to convert it. Reply please. ASAP.
pritaeas 2,194 ¯\_(ツ)_/¯ Moderator Featured Poster
See code above.
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