Hi Hi Hi
this solution is inverse of other solution that changed Decimal number to hexadecimal . It changes hexadecimal number to Decimal !
There is the other way to change characters to numbers.
Good Luck!
Hi Hi Hi
this solution is inverse of other solution that changed Decimal number to hexadecimal . It changes hexadecimal number to Decimal !
There is the other way to change characters to numbers.
Good Luck!
//16Radix number to Decimal
//Programming by : Erfan Nasoori
//Mail : ketn68@yahoo.com
//Date of send : 2009/1/9
#include<iostream.h>
#include<string.h>
#include<math.h>
#include<conio>
void main()
{
int k=-1,j,i;
double sum=0 ;
int x[20];
char hexa[16]={'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};
char s[20];
cout<<"Number in 16 radix : ";
cin>>s;
for(i=0 ; s[i] ; ++i)
if(s[i] >= 'a' && s[i] <= 'z')
s[i] -= 32;
for(i=0 ; s[i] ; ++i)
for(j=0 ; j<16 ; ++j)
if(s[i] == hexa[j])
{
x[++k]=j;
}
int y=strlen(s);
for( i=(y-1) ,j=0 ; i>=0 ; --i , ++j)
{
sum += (pow(16,i)*x[j]);
}
cout<<"--------------------------------------------------"<<endl;
cout<<"Radix 10 = "<<sum;
getch();
}
- Wrong headers used
- 'void main' used
- getch() used
- Bad formatting
Try again.
Please.
I wrote it by Borland 5.02!!!!!
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