C++ Integer to String function

Actually there is a standard method to do this using C++ string streams

int some_int = 10;
stringstream some_stream;
some_stream << some_int;
string some_string = some_stream.str();

I know you can achieve the same using string streams, but my goal was to do without ...

Still thanks for your reply !

A bit of an overkill don't you think? Also, your function can't handle negative numbers, mine can :D

string itos(int a) {
  if ( a == 0 )
    return "0";
  int sign = (a < 0 ? a = -a, 1 : 0);
  string result = sign ? "-" : "";
  char temp;
  while ( a ) {
    temp = '0' + a % 10;
    result.insert( sign, &temp, 1 );
    a /= 10;
  }
  return result;
}

Yeah, you're right William, but I was planning to rewrite the whole code for the reason you mentioned ...
My fixed code would also have used the modulo operator
(in that way I can finally get rid of that apow-function :P)

Nice to know is that I actually forgot to make it 'negative number'-friendly, thanks for mentioning that :) !!

Here's the final code of my itos-function, and you can see that I've completely rewritten it :) :

string itos(int a) {
	string sign = a<0?"-":"";
	string result = a>0?string(1,(a%10+'0')):string(1,((a=-a)%10+'0'));
	(a/=10)>0?result=itos(a)+result:result;
	return sign+result;
}

The ternary operator is my friend :P !!!

It works but I think it isn't very understandable anymore :P ...

A bit of an overkill don't you think? Also, your function can't handle negative numbers, mine can :D

string itos(int a) {
  if ( a == 0 )
    return "0";
  int sign = (a < 0 ? a = -a, 1 : 0);
  string result = sign ? "-" : "";
  char temp;
  while ( a ) {
    temp = '0' + a % 10;
    result.insert( sign, &temp, 1 );
    a /= 10;
  }
  return result;
}

Dear friends:
Could you please tell me what is the meaning of "&temp" in the result.insert.
i can not understand it.
Regards.

You MAY use this code for anything you want but you aren't allowed to sell this source

Hello, if anyone interested, I am selling the source code of a function that converts integer to a C++ string (just kidding :p)

temp is defined as type char at line 6. result is an instance of class string . There is no string.insert() method variant that takes a char argument, so the author used

string& insert ( size_t pos1, const char* s, size_t n);

which takes an array of characters (or a pointer to a character, same thing in C/C++) and a length (in case the character array or string, same thing in C) is not null-terminated. He is then passing a pointer to the character temp , which he creates by using the address-of operator & . Since he doesn't have a null-terminated array of characters, he also passes 1 to indicate that the "string" is just the one character in length.

temp is defined as type char at line 6. result is an instance of class string . There is no string.insert() method variant that takes a char argument, so the author used

string& insert ( size_t pos1, const char* s, size_t n);

which takes an array of characters (or a pointer to a character, same thing in C/C++) and a length (in case the character array or string, same thing in C) is not null-terminated. He is then passing a pointer to the character temp , which he creates by using the address-of operator & . Since he doesn't have a null-terminated array of characters, he also passes 1 to indicate that the "string" is just the one character in length.

thank you very much. I got it.