I've written a program to add two hexadecimal numbers ...
Njoy !
tux4life
/**********************************
* Written by Mathias Van Malderen
**********************************/
#include <iostream>
#include <string>
#include <sstream>
using namespace std;
string dec2hex(long a);
long hex2dec(const string & hexstr);
string hexadd(const string & hex1, const string & hex2);
int main()
{
string hex1, hex2;
cout << endl << "Type two hex numbers: " << endl << endl;
cout << "> First hex number: _______________\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b";
cin >> hex1;
cout << "> First hex number: _______________\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b";
cin >> hex2;
cout << endl << endl << "Sum of the two hex numbers: " << hexadd(hex1,hex2) << endl;
return 0;
}
string hexadd(const string & hex1, const string & hex2)
{
long n1, n2;
n1 = hex2dec(hex1);
n2 = hex2dec(hex2);
return dec2hex(n1+n2);
}
string dec2hex(long i)
{
stringstream ss;
string s;
hex(ss);
uppercase(ss);
ss << i;
ss >> s;
return s;
}
long hex2dec(const string & hexstr)
{
stringstream ss;
long i = 0;
hex(ss);
ss << hexstr;
ss.clear();
ss >> i;
return i;
}
If you also need subtraction, multiplication and division for hexadecimal number you only have to change the sign in the return instruction of the hexadd-function from '+' to -, *, /
...
You could just shove this in a class and overload the operators to do your operations, and to save time store the value as an integer till a call request the value in its HEX forum.
Wow, nice advice ! :)
Hi, good afternoon!!
Can I get this code in C, NOT in C++. please, I´m a newbie. and I'd like to understand the basic instructions and the logic for this Hex addition. Can you help me, please!! Thanks
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