Can anybody tell that when Inline won't work though we have declared function as inline. i.e code replacement won't take place .
saswatdash83 0 Newbie Poster
Ancient Dragon 5,243 Achieved Level 70 Team Colleague Featured Poster
its totally up to the compiler whether it honors the inline keyword or not, and there is no way to force the compiler to do it one way or the other, except maybe make the inline code a macro.
Salem 5,199 Posting Sage
*sniff* - smells like a homework question to me.
Here's one answer (for now) #define inline /* ha ha, no more in-lining today Jeeves */ I'll leave method number 2 for a day or so to add a sense of mystery and wonder (or merely just wait for someone else to post it).
vijayan121 1,152 Posting Virtuoso
inlining does not take place
in the presence (or absence) of some compiler switches / #pragma directives.
eg. presence of -fno-inline or -finline-limit=small_number / absence of -O in g++
for functions that are called using pointers obtained at runtime.
eg. C callbacks (the comparison function for qsort), C++ virtual functions called polymorphically
if the level of nested or recursive calls to inline functions goes above a certain implementation defined limit
Ancient Dragon 5,243 Achieved Level 70 Team Colleague Featured Poster
>>inlining does not take place
And at the discrection of the compiler at all times. The compiler can decide to ignore inlining at all times if it wants to. inline is only a suggestion to the compiler, not a requirement that it has to honor.
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